Thin-Walled Members and SHEAR FLOW in 10 MINUTES!!

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Shear flow analysis for calculating shear forces (for example, for applications with NAILS), and transverse shear stress in thin-walled members.

0:00 Shear Force vs. Stress
0:47 Shear Force Delta H
1:29 Delta H Equation
2:04 Shearing Force in Nails
2:49 Shear Flow Definition
4:22 Max Allowable Force
4:53 Thin-Walled Members
6:33 Shear Flow Diagrams
6:43 I-Beams
7:09 Box-Beams
8:22 Shear Flow Example

Transverse Shear Animation Excerpt:

First Moment of Area, Q:

Thickness, t (mention):

Parallel Axis Theorem:
Parallel Axis Theorem Examples:

Centroids:

Shear and Bending Relations, dM/dx = V:

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Previous Main Video Link:
Everything About TRANSVERSE SHEAR in 10 Minutes!! - Mechanics of Materials

Next Main Video Link:
Principal Stresses and MOHR'S CIRCLE in 12 Minutes!!

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20 Elastoplastic Beams and Residual Stresses (torsion too): coming soon
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Honestly well done,
After watching this i am convinced that my 'Professor' explaining the lesson has no idea what he is talking about, he literally just follows the marking scheme in his explanation without justifying what he is doing - like a robot - copy and paste without brain

Wish all lecturers were like you, you deserve more appreciation for the content you are providing
Keep up the good work
10/10

Stream_Function
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This is amazing. Thank you so much for uploading these videos. Also the way you clearly format your video description is incredible! Thank you so very much!!

dx-dt
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Thank you sir..
Shortly & perfectly explained the concept
This is 10 times better than our teacher

SouvikCivil
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YOU ARE AMAZING I SWEAR GOD THANK YOU <3

talalkanjo
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Nice and understandble explanation of engineering stuff. Very usefull in my work as engineer and refresh som theory.

jesperasserbo
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Thank you for this video! May I ask though what app is it that you are using to illustrate your answers? Thank you!

janwilfredcarpizo
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Thanks so much for your videos. Can you make a video on fluid mechanics - flow measurement - PLEASE

ayodelesamuel
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So I guess even though there's two nails, because the second is on the bottom and acting on a different interface you wouldn't multiply the allowable force by 2? I got double your answer because it is allowable force per nail and there were two nails XD

anotherperson
welcome to shbcf.ru