Algebra 67 - Deriving the Vertex Form of a Quadratic Function

The graph of a quadratic function in a single variable is always a parabola, and when the function is written in vertex form, we can identify the coordinates of the parabola's vertex simply by looking at the function. But how is the vertex form derived and why does it work? The process explored here involves shifting or 'translating' the basic quadratic function "a x-squared".

[Bedoroski]

Too underrated. We need more supporters on social media.😊

[newgood]

I would like to know how is the vertex formula -b/2a derived?

[sherkhanthelegend]

Why we using (scaled) x and y unit vectors here : 8:45 ?🙂

[daviandrade]

i'm from Brazil, I've appreciated your lectures. thanks professor Von Schmohawk

[robertjarman]

Can you make a video about sinusoidal functions? I love your videos and learn from them somehow better than my math teacher who has to go at a pace that incidentally, reflects a sinusoidal function.

[coffeedesbeans]

This is an awesome way to learn algebra.

[chinkeehaw]

Can you make a video about simultaneous equations?

[eksnq]

x^2=y
√y=x
And y=(x-3)^2
√y+3=x
Conclusion- so"x" shifts 3 positive units