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Prove that `|1+a1 1 1a+b1 1 1 1+c|=a b c(a+1/a+1/b+1/c)=a b c+b c+c a+a b`
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0:02:47
Prove that `|1+a1 1 1a+b1 1 1 1+c|=a b c(a+1/a+1/b+1/c)=a b c+b c+c a+a b`
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