Introduction to Karl Pearson's coefficient of correlation|Actual mean method|Dream Maths

Introduction to Karl Pearson's coefficient of correlation|Actual mean method|Dream Maths

Hello everyone,this is Bharti Sachdeva from Dream Maths.In this class you will learn about how to solve questions of correlation by actual Mean Method.

CHAPTER CORRELATION PLAYLIST

#correlation
#questions

[simranrajput]

You are the best maths teacher mam ❤️❤️
And the answer of the homework question is 0.865 😊

[Bigsound]

Calculating the Correlation Coefficient
Given:
* X: 10, 12, 15, 23, 20
* Y: 14, 17, 23, 25, 21
Steps:
* Calculate the means of X and Y:
* Mean of X (x̄) = (10 + 12 + 15 + 23 + 20) / 5 = 16
* Mean of Y (ȳ) = (14 + 17 + 23 + 25 + 21) / 5 = 20
* Calculate the deviations from the means for each data point:
* For X:
* 10 - 16 = -6
* 12 - 16 = -4
* 15 - 16 = -1
* 23 - 16 = 7
* 20 - 16 = 4
* For Y:
* 14 - 20 = -6
* 17 - 20 = -3
* 23 - 20 = 3
* 25 - 20 = 5
* 21 - 20 = 1
* Multiply the corresponding deviations for each data point:
* (-6) * (-6) = 36
* (-4) * (-3) = 12
* (-1) * 3 = -3
* 7 * 5 = 35
* 4 * 1 = 4
* Sum the products from step 3:
* 36 + 12 - 3 + 35 + 4 = 84
* Calculate the standard deviations of X and Y:
* For X:
* s_x = √[(Σ(x_i - x̄)²)/(n - 1)]
* s_x = √[(36 + 16 + 1 + 49 + 16)/(5 - 1)]
* s_x ≈ 4.36
* For Y:
* s_y = √[(Σ(y_i - ȳ)²)/(n - 1)]
* s_y = √[(36 + 9 + 9 + 25 + 1)/(5 - 1)]
* s_y ≈ 4.58
* Calculate the correlation coefficient (r):
* r = (Σ[(x_i - x̄)(y_i - ȳ)]) / [(n - 1) * s_x * s_y]
* r = 84 / [(5 - 1) * 4.36 * 4.58]
* r ≈ 0.864
Therefore, the correlation coefficient between X and Y is approximately 0.864. This indicates a strong positive correlation between the two variables.

[anshdubey]

Correct answer is so much mam for such a wonderful

[hamzaisraili]

Literally you are a saviour...i didnt have any idea about correlation and by just watching this video now the concept is clear ..really thanks to you mam..😊

[abdulazeem]

tomorrow is my exam and im doing it today but got confident after watched this video and under the concept and question as well.
JAZAKALLAH

[harshitatyagi]

Blessed to have you as a teacher in my life 😊😇

[sonamyadav]

Thank you mam for this video kal mera exam h Or apki video dekhne ke baad mujhe clear ho gya.... Mam answer would be 0.86

[abhayraj-xm]

Aapka padhane ka tarika bahut achha hai mam mai ek baar me samjh gya or ab to mujhe dobara ise revice krne ki jarurat bhi nii hai again thankyou mam

[_mnv]

submission x = 80, y= 100
mean of x = 16, y=20
submission(x-x bar)(y- y bar) = 84
submission(x-x bar) square = 118, submission(y - y bar ) square = 80

according to formula : 84 / square root of 118 * square root of 80 = 84/10.86 * 8.94 = 84 / 97.088

ans = 0.865

[inidhipal]

0.927 is the Ans of homework question aand thanks for these videos this is very helpful for us mam❤

[priyankarao]

Answer 0.865 thnku mam for this nice session ❤❤

[abhayraj-xm]

Aapka padhane ka tarika bahut achha hai mam mai ek baar me samjh gya or ab to mujhe dobara ise revice krne ki jarurat bhi nii hai 😢😢 again thankyou mam

[samikshadongare]

Wow! Such a great video, I got to see and learn. It helped me a lot to understand very Really impressed with ur teaching method💯

[peanutjelly_]

Ma'am I love the way you explain. No one else explains basic steps. Your videos provide another level of comfort. Thank you so much <3

[upadhyayian]

Thankful to you for these videos . They are my saviour to pass the exams. Keep it up and stay happy and healthy. And always make these kinds of videos ❤️❤️.

[ayushbhardwaj]

Mam mostly teachers explained like a youtuber ...but you explanation is too good and teaching methods, way, knowledge..superb mam superb 🙏🙏🙏🙏

[ishitathakur]

Thank you so much mam aapki videos se mujhe stats smjh aane laga h🥺 I have watched many of videos but yours are the one that really helped me alot❤️

[samay]

Karl Pearson's Coefficent of Correlation -
Q2. - Ans :- 0.865

[_viral_shorts]

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[sapnaias]

Wow kitna mst padha rhi aap👌
Ek bar me hi smjh me aa jye intna acha 😊