Relations and Functions | All From Basics | Lecture 1 | Class 11 Maths | JEE 2023 | Shimon Sir

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JEE English: Relations and Functions | All From Basics - Lecture 1 | Nurture | Class 11 Maths | JEE 2023 @Vedantu_JEE_English with your favourite Shimon Sir. Nurture series at Vedantu JEE Enthuse English to get your dream scores in JEE 2023 exams. In this session, we will take a look at all from the Relations and Functions basics Class 11 IIT JEE. We are here with 👉 today's session of Relations and Functions Class 11 IIT JEE | Relations and Functions Class 11 Maths | Relations and Functions IIT JEE | Relations and Functions JEE Mains 2023 | Relations and Functions Vedantu ​​​| IIT JEE Maths (Class 11 Maths Chapter 2) | JEE Main 2023 (IIT JEE 2023) ​session.

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✅ Assignment Solutions



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➡️ Topics Covered in this Session:
♦ Relations and Functions Class 11 IIT JEE
♦ Relations and Functions Class 11 Maths
♦ Relations and Functions IIT JEE
♦ Relations and Functions JEE Mains 2023
♦ Class 11 Maths Chapter 2
♦ JEE English

🎯 Vedantu JEE Enthuse (English) online class - Learn every detail of today’s topic Relations and Functions Class 11 IIT JEE | Relations and Functions Class 11 Maths ​​​| IIT JEE Maths (Class 11 Maths Chapter 2) | JEE English Online Classes | Online Coaching for IIT JEE | Online Classes for JEE | Vedantu JEE Enthuse English.

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Let us know if you come across any doubts 🤔 in today's Session "Relations and Functions | All From Basics | Lecture 1 | Nurture | Class 11 Maths Chapter 2 | JEE 2023" by Shimon Sir. #withme #learningwontstop
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HOME WORK : OPTION C
n(A)=4, n(B)=5
n(A)×n(B)= 4×5 =20
Thank you sir for your amazing class

gowrishankar
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Sir if we have lectures like you we no need to go for coaching for jee mains

ligergaming
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It's good to see master teacher from Tamil Nadu in vedantu Good sir u r teaching is very cool sir.teaching in English is too good sir

hariniudhayaragavan
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THANK YOU SIR FOR TEACHING.I UNDERSTOOD THE CONCEPTS VERY CLEARLY.

THE ANSWER FOR THE HOMEWORK QUESTION IS 20(OPTION C).

harinebhaskaran
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If i have a teacher like u, i will never hate maths sir ♥️

The_Black_Caps
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Your way of teaching is so good sir. U interact with students very well and give us some riddles to refresh ourselves :)

The_Black_Caps
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Super awesome session sir!
Homework answer: C)20

selvakkumarip
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OPTION C IS CORRECT
AWESOME SESSION ... REALLY LIKED IT 👍😊😊

PrakashYadav-vzob
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homework answer:option (c)=20 loved your session sir

abiramib
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Amazing session sir ! Answer for the home work question is option C.

fredricprabu
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Ans of homework is n(A*B) contains 20 elements option (c)

doubtapp
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Homework solution: n(A×B)= n( A) × n(B) =
4 × 5 = 20
Option C is the correct option.

fizanazir
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Just loved the way ur teaching sir!! I started getting interest on maths due to ur amazing lectures sir!!💫

rakshiiii
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n(a)×n(b)
4×5=20 option c is correct
Awesome session sir 👍

avantikamishra
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HW ans :C
Loved the session as always ❤️🔥🔥👀💯💯
Thank u 😊🔥
Peace✌️

leenasonnis
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sir ans:option C
reason: n(A)=4 n(B)=5
n(AxB)=n(A)*n(B)
4*5=20
MARVELOUS SESSION

shalinigovindaraj
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Answer of home work question is 20
Sol:
n(A×B)=n(A)×n(B)
n(A×B)=4×5
n(A×B)=20
Option C is correct

rajanibalduri
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HW ANSWER : C) 20
Amazing session 🔥🔥

kowsikadityaa
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Hi sir
I'm from Vellore and I listen to all your lectures and it is really awesome sir
Thank you so much for your teaching sir

keerthivasan
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Thankyou for the for the English explanation 😀👍

giff-ty-fulmarbaniang