Clipper Circuits

This electronics video tutorial provides a basic introduction into clipper circuits. This includes the positive and negative series clipper circuits as well as the parallel or shunt clipper circuits using diodes, resistors, and even zener diodes.

What Is a Diode?

How To Solve Diode Circuit Problems:

Diode Logic Gates - OR, NOR, AND, & NAND:

Clamper Circuits:

Half-Wave Rectifiers:

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Full-Wave Rectifiers:

Full-Wave Bridge Rectifiers:

220V AC to 12V DC Converter:

Capacitor Voltage Booster Circuit:

Half Wave Voltage Doubler Circuit:

Full Wave Voltage Doubler Circuit:

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Voltage Multiplier Circuit:

Light Emitting Diodes:

Power Dissipation In LEDs & Diodes:

Final Exams and Video Playlists:

Full-Length Videos and Worksheets:

[mehrabsubhan]

Hey man. You saved me so many times. I really appreciate your videos. I just wanted to thank you. I'm really grateful to you. Your teaching skills are amazing.

[eggxecution]

Remember when solving using kvl, the diode is parallel to RL, and therefore set the "Vout" at node between diode and RL. Solve for Vout and you'll get the (+) or (-) voltage.

Also if diode is ideal, no need for 0.7 drop. If not ideal it is given in problems.

[Hypotaksen]

I'm currently finishing my education as an electronics technician and these videos have been gold for studying. Please keep it up man.

[meask]

Bro, I am a teacher of electronics. You are doing a great job which is very useful to students all over the world. I was watching this video just to refresh the things after a long time and I found that at 8:50 the question you solved has wrong solution. Please correct it if possible. The question has potential divider and for a max input of 10 volt the potential drop across RL will be 5 volt only i.e. the diode remain off during the whole cycle and no portion of input will be clipped. Output will maintain sinusoidal waveform with a max voltage of 5 volt. Thanks

[Hamstercombat]

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[alirizvy]

ill be honest, u been uploading videos so in sync with my college sem and modules I have taken you to be my main teacher. im doing analogue electronics this sem and I really needed this. Thank you for all the work you put into this.

[aduedc]

You have great way of explaining things. I learned about these circuit.
@9:24 the maximum voltage is 5V, because the voltage divider divides it by two (10/2=5) and never gets to 6.7V, However, if your input voltage was say 20V then we get to 6.7V.
Thanks again for good clip.

[omegatechhd]

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[dudeontheinternet]

For the circuit at around 10:07...The output voltage will never go higher than 5V, because the peak input voltage is 10V. Vout=Vin/2, according to voltage divider rule, right? (Because RL is equal to RS in this particular circuit) So the peak output voltage is 5V. How can the output voltage be clipped at 6.7V if it never goes higher than 5V?

[manjulahebballi]

what is the significance of load resistance ?? what happens if we don't connect RL in parallel circuit?

[fabianralph]

The man, The myth, The

Gotta save this semester with this video!

[satabdikakati]

thank you so much it clears my all doubt lots of love from india

[paulp-gu]

Oh, so that's how it works thank you :)

[Man_searched_by_italy]

bruh finally a video with proper english

[Whysh_Path]

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[mehjabinmostafa]

this man teaches things more simpler than my course teacher. My course teacher literally came one day and started these maths with biasing without explaining this simple matters earlier.. thanks a lot maannn!!!

[張力文-bx]

Is the output signal at 11:24 possible? In my opinion, the diode would be all the way open cuz the voltage is distributed to two resistor. Thus, the potential across diode is not high enough to make the current go through.

[chijinkumar]

In 10:00 the diode will not be in on state for the given sine wave of amplitude 10 alteast 13.4V i.e 6.7*2 is required for diode to be ON.So the circuit will never clip.

[successthruknowledge]

Really stretched my mind with this lecture. I never heard of clipper circuits. Definitely learned a lot though probably I'll need to rewatch it one more time.

[avneeshsharma]

what about offset in output wave form???