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Minimum length subarray of an unsorted array sorting which results in complete sorted array
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Given an unsorted array of integers, find the shortest subarray, which upon sorting will result in complete sorted array.
Algorithm:
1: From the beginning of the array, move to element in the array up to which the elements are sorted i.e. where array[i] is greater than array[i+1]. Set startIndex = i.
2: From the end of the array, move to the element up to which the elements are sorted in reverse order i.e. where array[j-1] is greater than array[j]. Set endIndex = j.
3: Find the minimum and maximum elements in the subarray from startIndex to endIndex.
4: Search the sorted array from 0 to startIndex to find the index at which minimum element will be in sorted array say, minIndex.
5: Search the sorted array from endIndex to end of array to find the index at which maximum element will be in sorted array say, maxIndex.
6: Resultant sub array is the subarray between minIndex to maxIndex.
Order of the Algorithm:
Time Complexity: O(n)
Space Complexity: O(1)
Code and Algorithm Visualization:
Algorithm:
1: From the beginning of the array, move to element in the array up to which the elements are sorted i.e. where array[i] is greater than array[i+1]. Set startIndex = i.
2: From the end of the array, move to the element up to which the elements are sorted in reverse order i.e. where array[j-1] is greater than array[j]. Set endIndex = j.
3: Find the minimum and maximum elements in the subarray from startIndex to endIndex.
4: Search the sorted array from 0 to startIndex to find the index at which minimum element will be in sorted array say, minIndex.
5: Search the sorted array from endIndex to end of array to find the index at which maximum element will be in sorted array say, maxIndex.
6: Resultant sub array is the subarray between minIndex to maxIndex.
Order of the Algorithm:
Time Complexity: O(n)
Space Complexity: O(1)
Code and Algorithm Visualization:
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