Trick Question: Cascaded Exponents

[skonaslp]

It physically hurt me to see him write 1^∞=1

[grqqn]

do yall actually get multiple choice math questions in the US

[KiWith]

1 to the power of anything is always 1, except for what you wrote: 1 to infinity. This is undetermined.

[javidan]

i pluged it into my calculator and it said the answer was Sheesh

[kushalahmed]

Imagine a 'Sheesh' option in school exam

[JeremyLionell]

You actually tricked me...
I thought you have to work your way from the bottom...

[sulemanaziz]

By watching your videos, I was finally able to solve this one by myself. Thanks for teaching well 🥰

[carlosffm]

This only works because it is 4^((((1^2)^5)^9)^8)
But if it is not explicit or you are not familiar with the font, it could be read as: which would give you a different result, neat idea, but ir depends on you noticing the size and location of the already very small print exponents

[gilangsuryadharma]

I like this channel alot, by far teaches me how to tackle mental model difficulties

[quoddie]

Thank you. Want to see this recommended more often

[YamamotoTV]

Did anyone notice how he didn’t even type the “8” into his calculator?

[utkarshsrivastav]

Even thought this process is correct but saying that 1^(infinty)=1 is wrong as it is an indeterminate form and we have a few ways of solving this limit which more often that not results in e^n where n can be any expression or no.

[wlaeiogn]

I think there is about the priority in solving process. If you prioritise the exponent part then you can do as the video shown. If you prioritise the base part then you have to expand it according to the power, in other words you have to multiply the exponents together. But I'm not sure which one is correct or both of them are acceptable.

[soulsofwar]

Depending on how you group it, it is either 4 or 4^720

Keep in mind that (x^y)^z=x^(y*z)
So if you group it that way, then this is 4^(1*2*5*8*9)

However if you group it like 4^(1^(2^(5^(8^9)))) then it does simplify to 4^1 since 1^anything=1

[omaanshkaushal]

Shouldn't it be 720, we multiply the exponents to the exponents?

[otavioluz]

1^ inf does not result in number is a limit

[TheoWerewolf]

To clarify and explain rather than just going for shock value (in a math video of all places).. the order of execution is PEMDAS, so you have to start at the outermost exponent first and work inwards. Regardless of what the result of everything above it is, when you get to 1, 1 to the power of anything (other than 0) is 1. So 4^1 which is 4.

[mohamedyasser]

Wrong point 1^infinity isn't equal to 1, it's undefined

[Tmplar]

One elevated to infinity is not the same thing as one elevated to any number

[tolberthobson]

That statement "1 to the power of literally anything is just 1" IS VERY INCORRECT!!!