Calculation of de Broglie wavelength of the electron

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An electron microscope uses an electron beam of energy E=1.0 keV. Can this microscope be used to obtain the image of an individual atom? (The size of an atom ~10^{−10} m.)
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That really helps !!
Lov from India ❤️

Your_desi_physio
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Dude! today you just helped me in my calculations of nuclear BE, and now you also helped me with my QM's. I couldn't help subscribing to your channel.

madrasamahmudefendimexico
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Hello friend your given answer is correct because you have used nonrelativistic equation of wavelenth. if we have given k.E of electron is 500KeV so this energy is approximately equal to rest mass energy of electron(511Kev). So at that tine we want to use relativistic equation of wavelength.

filmitech
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on what are you writing is it a mirror ?

billubiologistbb
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Hi, what are the markers do you use?. Greetings from Mexico

enriquesalazar
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Are you writing on the glass backwards?

Wody
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Really thnx u saved me for exam ..love from india

story-nfpy
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For an electron with kinetic energy of 50 ev, why is the 50 ev treated as kinetic energy and not the total energy of the electron?

unclesammy
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Do we need to consider relativistic effect ?

udaybhattacharjee
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Why can't we use{ (lamda) = hc/E }

swegattyswooty
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Please help....what voltage must be applied to an electron microscope to produce electrons of wavelength 0.4A°

jasschannel
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Sir pls explain thise formula lyamada=h÷root 2mq×v

bimannabimanna
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Please help....light is a wavelength of 300nm hit a certain surface with wave function 2.26ev calculate the kinetic energy and speed ejected electron if the mass of electron is 1.3×10^-31kg

orjijoyce
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Etem ha ha by the way nice explanation, keep it up

UCSAdityaKumarChoudhury