AP / AB Calculus Test - Sample Questions 9 & 10

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  1. Patrick J
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Комментарии
Автор

yep - lots of way to do these problems!

patrickjmt
Автор

Help!! What happened to videos for questions 5 & 6 and 7 & 8? For some reason these two are private.  I asked my students to work through this test with you over spring break.  Any chance you could make them public for the next week or two? 

APCalcCW
Автор

Please correct me if I am wrong.
Just before taking the second derivative, f'= -2cosx sinx, it could be used also the approach of sin(2x) = 2six cosx. Therefore, the exercise would look like:
f'= -2cosx sinx
f'= -2sinx cosx
f'= -sin(2x)
f"= -cos(2x) 2
f"= - 2 cos(2x)
f"(pi) = - 2 cos(2 pi)
f"(pi) = - 2

luissr
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f'(x) = -2 sinx cosx = -sin(2x)

f"(x) = -2cos(2x)

f"(pi) = -2cos(2pi) = -2(1) = -2

mathewgeorge
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wait did you say the intgral of 1+x^2 is arctan i thought it was x+1/3x^3 by using the rule x^n+1/n+1 so how is it arctan?

MathMikie
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Can't you just say that -2cosxsinx is the same as -sin2x and then differentiate and get -2cos2x?

supergsx