Arrays in Java (Exercise 3)

Java Programming: Programming Question on Arrays in Java Programming
Topics Discussed:
1) Writing a program that displays the number of occurrences of an element in the array.

Music:
Axol x Alex Skrindo - You [NCS Release]

#JavaByNeso #JavaProgramming #ArraysInJava

[vishnuvp]

int occ = 0;

for(int j : numbers)
if(j == searchelement)
occ++;
return occ;

you may try this!!

[devanshsolani]

These exercises are really helping
Can you make one playlist dedicated to Java Problems and their solutions?

[Relge]

These videos are very helpful!! Much appreciated.

[deep]

int [] arr = {1, 1, 1, 2, 3, 4};
int searchElement = 1;
int duplicate = 0;
for (int i = 0;i<arr.length-1;i++){
if (searchElement==arr[i]){
duplicate++;
}

}

[micheljohn]

Please upload OOPs videos quickly! My exams are coming soon!

[kostavsheoran]

well i made a program that searches every different no. in an array and display its no. if occurences for a greater challenge !, however these exercises are really important in learning programming !

[Qingyao-pl]

public class ArrayExercise3 {
public static void main(String[] args){
int[] numbers = {1, 1, 1, 2, 3, 4};
occurrence(numbers, 1);
occurrence(numbers, 2);
occurrence(numbers, 3);
occurrence(numbers, 4);
}
private static void occurrence(int[]numbers, int num)
{
int count = 0;
for(int i = 0; i < numbers.length; i++){
if(num == numbers[i])
count++;
}
System.out.println("The occurrence of " + num + " is "
+ count + " times.");
}

}

[thivagarmurugan]

public class methods {
public static void main(String[] args) {


int [] array= {1, 1, 3, 4, 3};
arrayCount(array);
}
public static void arrayCount(int [] array)
{
Scanner num=new Scanner(System.in);
int n=num.nextInt();
int count=0;

for (int i=0;i<array.length;i++)
{
if (n==array[i])
{

}


}
System.out.println("the count"+" "+ n +" "+"count="+count);

[njaliShinde]

please regularly upload further videos

[kevinbanan]

public class övning3 {

public static void main(String[] args) {

int[] arr = {1, 1, 1, 2, 3, 4};
int n = 1;
int count = 0;

for (int i = 0; i < arr.length; i++) {
if (arr[i] == n) {
count++;
}
}
System.out.println(n + " occured " + count + " times.");
}

}

[hamitkoca]

public class Array_Exercise3 {
public static void main(String[] args) {

int [] numbers={1, 1, 1, 2, 2, 3, 4, 4, 5, 6, 7, 7, 8, 9, 0, 0};
int occurs0=0;
int occurs1=0;
int occurs2=0;
int occurs3=0;
int occurs4=0;
int occurs5=0;
int occurs6=0;
int occurs8=0;
int occurs9=0;
int occurs7=0;
for (int i = 0; i<=9; i++){

for(int j=0;j< numbers.length;j++){
if (i==numbers[j]){

if(numbers[j]==0){
occurs0++;

}else if(numbers[j]==1){
occurs1++;

}else if(numbers[j]==2){
occurs2++;

}else if(numbers[j]==3){
occurs3++;

}else if(numbers[j]==4){
occurs4++;

}else if(numbers[j]==5){
occurs5++;

}else if(numbers[j]==6){
occurs6++;

}else if(numbers[j]==7){
occurs7++;

}else if(numbers[j]==8){
occurs8++;

}else if(numbers[j]==9){
occurs9++;

}
}


}

}
System.out.println("occurs0 = " + occurs0);
System.out.println("occurs1 = " + occurs1);
System.out.println("occurs2 = " + occurs2);
System.out.println("occurs3 = " + occurs3);
System.out.println("occurs4 = " + occurs4);
System.out.println("occurs5 = " + occurs5);
System.out.println("occurs6 = " + occurs6);
System.out.println("occurs7 = " + occurs7);
System.out.println("occurs8 = " + occurs8);
System.out.println("occurs9 = " + occurs9);



}

[ankit_gurjar]

If we want to count occurance of all the number then?

[acunit]

import java.util.ArrayList;
import java.util.Arrays;
import java.util.Scanner;

import static
public class Main {

public static void main(String[]args){
ArrayList<Integer> integers = new ArrayList<>();
Scanner input = new Scanner(System.in);

while (true) {
displayMenu();
System.out.println("Enter your choice");
int choice = input.nextInt();

if (choice == 1) {
System.out.print("Enter an integer: ");


} else if (choice == 2) {
System.out.print("Enter an integer to remove: ");
int elementToRemove = input.nextInt();

if {


} else {
System.out.println("Element not found");
}
} else if (choice == 3) {
System.out.println("Your list: " + integers);
} else if (choice == 4) {

break;
} else if (choice == 5) {

System.out.println("Enter values that you want to search in this array");
for(int ii = 0; ii < 3; ii++) {
var x = input.nextInt();
var sum = 0;

for (int i = 0; i < integers.size(); i++) {
if (integers.get(i) == x) {
sum += 1;
}
}
System.out.println(x + " occurs " + sum + " times");
}
}

}
}

private static void displayMenu() {
System.out.println();
System.out.println("1. Add");
System.out.println("2. Remove");
System.out.println("3. Display");
System.out.println("4. Exit");
System.out.println("5. Display integer occurrences");
System.out.println();

}
}

[Shivam-ehfc]

Please upload the next video lectures of java!

[suswithcherry]

import java.util.*;

class Check {

public static void main(String[] args) {

Scanner input = new Scanner(System.in);
System.out.print("Enter the size of the array: ");
int size = input.nextInt();

int[] numbers = new int[size];
fillArrayOfIntegers(numbers);

System.out.print("Enter an integer to know its no.of occurrences in the array: ");
int n = input.nextInt();

int occurrence = occurrencesOfAnInteger(numbers, n);
if(occurrence > 0)
System.out.println("Integer "+ n +" occurred for " + occurrence + " times in the array.");
else
System.out.println("Integer " + n + " is not present in the array.");
}

private static void fillArrayOfIntegers(int[] numbers) {
Scanner input = new Scanner(System.in);

for(int i = 0; i < numbers.length; i++) {
System.out.print("Enter an integer: ");
numbers[i] = input.nextInt();
}
}

private static int occurrencesOfAnInteger(int[] numbers, int n) {
int count = 0;

for(int i = 0; i < numbers.length; i++) {
if(numbers[i] == n)
count++;
}

return count;
}
}

[YazeedSeraj]

Your exercise statements are sometimes ambiguous