cosec a - sin a sec a - cos a=1/tana+cota

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Prove that (coseca-sina)(seca-cosa)=1/tana+cota. Direct proof of (coseca-sina)(seca-cosa)=1/tana+cota. Show that sina/seca+tana-1+cosa/coseca+cota-1=1. (coseca-sina) (seca-cosa) =1/tana+cota. coseca-sina×seca-cosa=1/tana+cota. Prove that sina/seca+tana-1+cosa/coseca+cota-1=1. 1+cota/cosa+1+tana/sina=2(seca+coseca). (tana+cota)(coseca-sina)(seca-cosa)=1.
  1. NumberX
  2. prove that (coseca-sina)(seca-cosa)=1/tana cota
  3. (coseca-sina) (seca-cosa) =1/tana cota
  4. coseca-sina×seca-cosa=1/tana cota
  5. prove (coseca-sina)(seca-cosa)=1/tana cota
  6. (tana cota)(coseca-sina)(seca-cosa)=1
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Комментарии
Автор

Sir I had a doubt, if I do the reciprocal of sinA.cosA and then apply identity and then at end reciprocate again, will that work?

anveshpandita
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It is more easy when we use LHS and RHS seperately

BROOKLYN.___.
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It will be more easier if we keep cosa x sina and then solve 1/tana + cota to bring it as LHS ❤❤..

Saad_thenics
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1/(sin)²+(cos)²/(sina+ cosa) kyu likha gaya hai

SanjayKumar-nmrj