EULERS PARTIAL DERIVATIVE If u=tan^-1(x^3+y^3)/(x-y) prove xӘu/Әx+yӘu/Әy = sin2u

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EULERS PARTIAL DERIVATIVE If u=tan^-1(x^3+y^3)/(x-y) prove xӘu/Әx+yӘu/Әy = sin2u

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Can u explain Euler's extension theorem for this sum?

kunchalalaxmi
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Can u mention by which formula sec^2 is converted as sin2u

kesariprabhakar
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How 2tanu/sec2u convert into 2sinucosu please help?

JeevanKumar-glmu