Epsilon Delta Limits in 4 Minutes

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An explanation for understanding how the delta epsilon definition of a limit is derived! We have to think about what it means to approach a particular value.

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I watched this twice and I now understand half of it. Progress!!

GuideInTheTrees

this was actually so helpful. thank you so much! ive been watching a lot of epsilon delta videos since my teacher’s lecture made no sense and this is definitely the clearest one i’ve found so far

stop

the fact that his shirt says the video is just really cool

ynnx

Oh thank god, my prof just sort of dropped this on us last week and I had no idea what I was doing. Its really helpful to hear the _context_ in which these problems exist so that I know what I'm looking for and why I need to do certain things.

leokeatonn

That was a truly brilliant explanation.

TrackopGaming

0:25 - 0:50 was especially impressive, the word choice was very clear and concise. I could tell that took a few takes, and not just cuz of the jump cuts. How much time do you spend on "scripting" these videos?

nathanisbored

Easily the best epsilon delta on youtube, I would say even better scripted than 3B1B's brief explanation. Well done.

gopackgo

Thanks! Extremely clear and concise explanation.

jasonzechengpan

YOU JUST SAVED MY LIFEEE !!! Thank you so much x

queena

I had to watch some parts multiple times but it was worth it, I think I finally got it :D

alejrandom

I have a comment to make. When solving the questions we find a value of epsilon from |f(x)-L|, such that, it is in terms of |x-c| and some other constant term(s). This establishes the connection between the |f(x)-L| interval and |x-c| interval. Now if we squeeze |x-c| interval then |f(x)-L| interval gets squeezed too, since those two are connected. When we can establish this connection through algebraic manipulation we say that the limit exists. Geometrically this makes sense. When we narrow the interval around c the interval around L gets narrow too. Also remember: |f(x)-L| and |x-c| are intervals.

moazzamjadoon

When we are explaining the problems with it and we suppose the limit is m instead of L, are we considering |f(x)-m| instead, and saying that there will be an epsilon such that |f(x)-m|<epsilon?

Adam-wmys

Kudos to our distinguished young man! I never had this concept in calculus, and the Schaum outline series didn't help. Why don't they teach it with visuals? I am visual, and this approach helps tremendously.

BuddyNovinski