Conversion of Epsilon NFA to NFA - Examples (Part 2)

TOC: Conversion of Epsilon NFA to NFA - Examples (Part 2)

This lecture gives shows how to convert a given Epsilon NFA to its equivalent NFA

Music:
Axol x Alex Skrindo - You [NCS Release]

[jennyfisher]

I think there is one mistake: when you calculate Q at C direction, it can go to C itself and P as well. Look at the first step P.

[orth-dimensionalamansagar]

He teaches so good
So his students could find thier mistakes
And correct thier answer
THANK YOU NESO .

[HemantKumar-wsxl]

sir there is missing a p in third table.
Q on input C it goes to Q and P.

[masoud]

Thanks for the tutorial .
Q on input c goes to P and Q and in it's equivalent NFA, Q on c goes to {P, Q, R}

[Nirala_]

Here One mistake becomes huge mistake .
But it's okay we have got it correctly.
Thanks a lot sir for your efforts 💚

[inderjeetchawla]

Chill guys just thank him for teaching so good that now you are correcting him.

[yatridavda]

Q on input C it goes to P as well that not considered in this video so the null closure of Q for C is {P, Q, R}

[amrikdutta]

Thank you so much ...you guys teach so good .. i am learning from this channel for past 2 semesters.. thank you so much neso

[danielwintermeyer]

When you check the c input for State Q then on checking the 2nd epsilon why did you not include state P. State Q in c input will have {P, Q, R} in it's final states.
Please Verify.

[digamberkhandebharad]

Sir on getting input 'c' we can go itself and 'p' also

[abhishekbhardwaj]

Bro taught everyone so well that he himself got behind😂

[imritam]

Sir...state Q on getting the input c it goes to Q itself and P, and P on getting input c it goes to R...So the 2nd €* will be P, Q, R...

[elyasaf]

Sir, Q on getting C to Q & P. so in the NFA, P on getting C goes to {P, R, Q}
Thank you so much for the videos! you are a saviour!!

[anushreevirtualgaming]

Sir on getting input 'c' we can go itself and 'p' also
so the answer should be {p, q, r}

[rajuneupane]

Sir I follow your videos very much ....sir thank u for making these videos for us these videos are d only hope sir ...sir during third transition u didn't went to p state wen se got c as a input ....y sir. think it should be Q->C = p, q, r

[ashukashyap]

At 4.00 the q can also goes to p then the closure of p is {p, q, r} so the final output of q with tha transaction c is {p, q, r}

[pankushmahajan]

Transition(Q, c) results in P&Q instead of Q only
Isnt it?

[OneStopShorts]

Sir in P state in C input the right answer is {P, Q, R} (because Q-c->{Q}, {P}-epsilon*->{Q}, {P, Q, R} and union of Q and P, R, Q is {P, R, Q} )

[kingprince]

You made a mistake somewhere Sir. A "c" input in state "Q" can either go to state "P" or remain in state "Q". Anyway Thank You Sir, You teach so well that I understand! 😎

[Dacapoelcodaa]

i mean its ok to make mistakes while teaching, but not ok to discover them and not publish! i spent time doubting and searching in the comments