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Day 6 Bitwise Operators HackerRank JavaScript
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10 Days of Javascript, HackerRank Day 6 Bitwise Operators
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Solution explanation:
Because K less or equal N the condition (K-1 OR K less or equal N) is always true in cases where K-1 is even.
In cases where K-1 is odd, the condition (K-1 OR K less or equal N) sometimes evaluates to false (the lowest higher number is bigger than N), in which case the answer is K-2. When it evaluates to true, the answer is K-1.
Please subscribe, like, and share for more new videos on the YouTube.
Solution explanation:
Because K less or equal N the condition (K-1 OR K less or equal N) is always true in cases where K-1 is even.
In cases where K-1 is odd, the condition (K-1 OR K less or equal N) sometimes evaluates to false (the lowest higher number is bigger than N), in which case the answer is K-2. When it evaluates to true, the answer is K-1.
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