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Solve: (3x)^log3 = (4x)^log4
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Solve: (3x)^log3 = (4x)^log4 Thanks for watching.
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Solve: (3x)^log3 = (4x)^log4
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3x^log 3 = 4x^log 4. Literally 99% could not do it!
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Consider the equations `(3x)^(log3)=(4y)^(log4)and 4^(logx)=3^(logy)` Answer the following
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How to solve for 'X' in this logarithmic equation. #equations #logarithmic (3x)^log3=(4x)...
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log4 (4x-1) = 2
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solve log(3 + x) - log(x - 2) = log 4
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log4(3x + 2) = log4(5) + log4(3), solve for x
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Solve : `3log_x(4)+ 2log_(4x)4+3log_(16x)4=0`
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