Relation between n(A), n(B), n(AUB) and n(AnB) || Sets || Class 10 Maths

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Relation between n(A), 0:01:11

Relation between n(A), n(B), n(AUB) and n(AnB) || Sets || Class 10 Maths

How to prove 0:05:58

How to prove that; n(AUB)=n(A)+n(B)-n(AnB)

##n(A U B 0:00:28

##n(A U B ) = n(A) + n(B) - n(A intersection B)

n(aubuc)=n(a)+n(b)+n(c)-n(a∩b)-n(a∩c)-n(b∩c)+n(a∩b∩c) proof 0:08:02

n(aubuc)=n(a)+n(b)+n(c)-n(a∩b)-n(a∩c)-n(b∩c)+n(a∩b∩c) proof

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Prove that n(AUB)=n(A)+n(B)-n(A∩B) 0:03:57

Prove that n(AUB)=n(A)+n(B)-n(A∩B)

Proof of n(aub)=n(a)+n(b)-n(anb) 0:03:38

Proof of n(aub)=n(a)+n(b)-n(anb) by Venn Diagram || Union of 2 Sets || a union b Venn diagram

Calculate n(A intersects 0:02:38

Calculate n(A intersects B) given n(A union B) n(A) and n(B)

Verify n(AUB)+n(A intersection 0:00:50

Verify n(AUB)+n(A intersection B)=n(A)+n(B)

A and B 0:03:28

A and B are subsets of S such that n (S) =50, n(A’) = 20, n(B’) = 25 and n(A ∩ B)’ =40 then n(AUB)...

n(A U B) 0:00:31

n(A U B) = n(A) + n(B) - n(A ∩ B) / Formula verification of n ( AU B)

n(AUB) formula sets 0:02:35

n(AUB) formula sets class 10

UNDERSTANDING n(AUB) = 0:09:47

UNDERSTANDING n(AUB) = n(A) + n(B) - n(A∩B)

Let A and 0:01:03

Let A and B be finite sets such that n(A)=20, n(B)=28 and n(A∪B)=36 find n(A∩B)

Relation of nA,nB 0:02:30

Relation of nA,nB and nAUB

if n(A)=12,n(B)=8,n(AnB)=4,n(AUB)=. Class 0:00:53

if n(A)=12,n(B)=8,n(AnB)=4,n(AUB)=. Class 11 maths sets #shortvideo

find A U 0:03:02

find A U B and find n(A U B )

n(AuB)=n(A)+n(B)-n(AnB)//prove//part 13 0:21:07

n(AuB)=n(A)+n(B)-n(AnB)//prove//part 13

n(A)=14 , n(B)=10 0:02:02

n(A)=14 , n(B)=10 and n(AnB)=18 then find n(AU)=18 then find n(AuB).

FORMULAS ON CARDINAL 0:13:44

FORMULAS ON CARDINAL NUMBER n(A) + n(B) = n(AUB)

How to find 0:01:50

How to find n(AUB) and n(U)|| Sets Short Question|| Class 8|| Class 9||Class 10||

n(AUB) = n(A) 0:16:38

n(AUB) = n(A) + n(B) - n(AnB) | Class 11 Maths Chapter 1 NCERT | Lec.15

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