JAVA : What is the output of the following Java code snippet?

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JAVA : What is the output of the following Java code snippet?

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JAVA : What is the output of the following Java code snippet?

int x = 10;
int y = 20;
Options:
A) x + y = 30
B) x + y = "30"
C) x + y = 1020
D) x + y = "1020"

Answer: Option D) x + y = "1020"

Explanation:

In the given code snippet, the concatenation of string "x + y = " and integer value of x is performed first using the + operator.

This results in a string "x + y = 10". Next, the integer value of y is also concatenated to the string using the + operator, resulting in the final string "x + y = 1020".

The resulting value is a string, not an integer, which is why the correct answer is D) x + y = "1020".
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JAVA : What is the output of the following Java code snippet?

int x = 10;
int y = 20;
System.out.println("x + y = " + x + y);
Options:
A) x + y = 30
B) x + y = "30"
C) x + y = 1020
D) x + y = "1020"

Answer: Option D) x + y = "1020"

Explanation:

In the given code snippet, the concatenation of string "x + y = " and integer value of x is performed first using the + operator.

This results in a string "x + y = 10". Next, the integer value of y is also concatenated to the string using the + operator, resulting in the final string "x + y = 1020".

The resulting value is a string, not an integer, which is why the correct answer is D) x + y = "1020".

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String concatiation is performed in this rather than addition so answer is x+y=1020

Maheshdy
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