☑️17 - Thevenin's Theorem: Circuits with Dependent Sources 1

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In this lesson, we shall learn how to solve linear circuits involving dependent sources using thevenins theorem.

When solving a linear circuit with dependent sources using thevenin's theorem....
1. Deactivate all independent sources, mark the terminals and leave all dependent sources alone.
2. Introduce either a 1v source or 1A current source in between the two terminals
if you introduce Vo = 1, then we find io, but if you introduce io = 1, then you find Vo
3. The attempt is to find Rth, Rth = Vo/io
4. Find Vth from the original circuit, Vth is the open circuit voltage betwee the terminals ab

00:00 - Example 1
12:41 - Example 2

Playlists on various Course
1. Applied Electricity

2. Linear Algebra / Math 151

3. Basic Mechanics

4. Calculus with Analysis / Calculus 1 / Math 152

5. Differential Equations / Math 251

6. Electric Circuit Theory / Circuit Design

Make sure to watch till the end.
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Bro is dangerous 💀, I mean he is using loop equation rather than KCL or nodal. Damn bruh❤

koushiksamanta
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Thank you
To help me in clearing my mid sems ❤❤

nishantgupta
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THANKS SIR WE BE GETTING 90'S BECAUSE OF YOU😭😍😍😍😍😍😍😍😍😍😍😍😍😍

mohubemahlatsephaladi
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i thought Vx in example 2, was supposed to be Vx= 15(Ix)

KwizeraPacifique-xfdd
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Hi! May I know why are there two value of Ix? What is the difference between the Ix obtained in solving the resistance vs the Ix obtained in solving the voltage?

nishjijiiiii
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Hello sir, in example 2 when we found i1 it is in fraction if we change it to decimal it is 0.66A so in i0 when we replace i1 to find it it will be -1.32A hence, isn't Rth Vo/io = 1/-1.33 = -0.76 ohms. so only because i changed the fraction to a decimal it changed the answer totally?? if so then when should i just keep it as a fraction and when should i change it to decimal?

zaidabdulkarim
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In example1, why the current flowing through the 5ohn resistor is 0.5 Ix?

GenerousChicken
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sir, for calculating the Vth in the example2, can I set the different positive and negative resistor terminals and write the equation as 4Vx+10Ix-5Ix+15Ix=0?

szcf
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Thank you very much for this awesome video!

erdal.uzunlar
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What was the purpose of the polarity over the 5 ohm for vx .Shoudnt the voltage across ir be -5Ix.Since in the direction assumed there will be a negative drop?

danthetutor
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is Vth always 0 if there are only dependant sources? like it was in example 2 since there are no independent sources to provide voltage.

mokhtarnasser
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while finding vth at example one does no current flow from the 6v battery and we only consider 0.5 Ix?

irisianacani
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You had two different values for the same variable Ix... why are they different..
And does the Vth only affect that loop

KinguinMalfoy
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Rth= Vth/Isc and Isc across load is Ix so Rth=4ohms
What is wrong with this

confused_engineer
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Sir
Does this tutorial video meant for senior high school level or university

aliekamaraa
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How is it possible that the voltage drop across 4 ohm resistor is 5.33V? That means 5 ohm and 3 ohm resistor only dropped 0.67V from the 6V battery. Can you please explain that?

hleketanicarl
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in example 1 why did u subtract 1.5 from 1

khalid
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isnt the current in the 15ohm resistor ( i0-i1)-(i1 since i1 is also going through 15 ohm in the opposite direction ?

viwemkhothi
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Please 2:25
What if you use Io=1A. How one now find vth
Please sir

dcmar-ava
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This is contradicting to content I read from Basic engineering circuit analysis by David Irwin 11th edition page 192, I suggest u check that page and see where u go wrong if at all u are wrong

lugandaronald