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`a(cosC-cosB)=2(b-c)cos^2A/2`
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`a(cosC-cosB)=2(b-c)cos^2A/2`
In `triangle ABC`, prove that `a(cosC-cosB)=2(b-c)cos^2.(A)/(2)` .
Prove that:- a(cosC - cosB) = 2(b - c) cos²A/2
`a(cosC-cosB)=2(b-c)cos^2A/2`
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