An electric field given by pierces the gaussian cube

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An electric field given by E = 4.0i – 3.0(y^2 + 2.0)j pierces a Gaussian cube of edge length 2.0 m and positioned as shown in the figure. (The magnitude E is in newtons per coulomb and the position x is in meters.) What is the electric flux through the (a) top face, (b) bottom face, (c) left face, and (d) back face? (e) What is the net electric flux through the cube?

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an absolutely brilliant explanation, this 9 mins of the video is far better then my 3 hours applied physics class honestly

Streltsi_

You saved my physics homework grade and ultimately make more sense than my professor or textbook. Thank you so so much

ellaabennett

You're such a W, much better than my physics teacher

pablofoster

Thanks it really help me in question solving

rajatyadaw

THANK YOU SO MUCH!!! Brilliant explanation.

paulah

How do we know the electric field lines because if dA is perpendicular to E than flux is going to be zero

ArthurMorganFTW_RDR

Why do you not treat 4i and -6j as constants in this field?

steezetothestokes

Thanks for helping me so much best explanation ever.

dhruvilshah

ياخي انت اسطورة, احببتك في الله, يارب تسلم

-o

Plzz help me with this question
A closed surface with dimensions a = b = 0.4m and c = 0.6m is as shown above. The left edge of the closed surface is located at the point x = a. The electric field through the region is nonuniform and is given by E = (3 + 2x^2)în/C, where x is in meters. (a). Calculate the electric flux leaving the closed surface. (b). What is net charge enclosed by the surface.

ikshasharma

tf bro you should teach in my university man . bravo. understood every single word you said. you have a new student 😊 your physics is masterclass
top G 😂

ShadeMusicVibe

thanks for helping me survive phys 259

niazomatic

Great video! Super helpful....you explain it do well. Thank you!

buhlendlovu

Sir I have a question if the variable vector in case of back face is known then what will be flux through it

montukumar

Great tutorial, thanks for the explanation.
One question though, when you're doing the dot product
of dA and E, why does dA remain afterwards again,
whereby its (-18)dA? Would it not disappear after you did the dot product?

cloudandtree

Why does the R and L faces have the same flux while the T & B do not have the same flux?

everybodyknowsme

This is very easily explained, Thank you sir

Legend_Hunter_Original

Great video. If someone can help me what happens when we have a field like this E = (3.0 Nm/C)i + 4.0N/Cj. Because in the ppt of my class says that the top face is -12Nm^2/C but i can't find an answer to justify that and for the right face it says that it's 16Nm^2/C. If someones know I'll appreciate a lot.

davidhurtado

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