ABCD is a parallelogram.AB is divided atPandCDatQsothatAP:PB=3:2andCQ:QD=4:1.IfPQmeetsACatRthenprove

preview_player
Показать описание
@dhanab_onlinelecture724
@viral724pathak
ABCD is a parallelogram . AB is divided at P and CD at Q so that AP : PB = 3 : 2 and CQ : QD = 4 : 1 . If PQ meets AC at R then prove that AR = 37AC .
#triangle #similartriangle #math #ncert #cbse #class10
Рекомендации по теме