In the adjoining figure D is the midpoint of BC of a ∆ABC. DM and DN are the perpendiculars on AB&AC

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In the adjoining figure D is the midpoint of BC of a ∆ABC. DM and DN are the perpendiculars on AB and AC respectively and DM=DN then the ∆ABC is:

(a) right angled (c) equilateral

(b) isosceles (d) scalene
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Equilateral triangle nhi ho skta h kya sir

SujitKumar-djrg