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Integral of ∫cot^2(x)dx
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In this video, we find the integral or anti-derivative of cot^2(x). We approach this by first revising the derivative of cot(x), which equals -csc^2(x).
Then, by the Pythagorean Trigonometric identity: cot^2(x) + 1 = csc^2(x). We can rearrange this equation to:
cot^2(x) = csc^2(x) - 1
Realising that -csc^2(x) derivative of cot(x), we can write the above as:
cot^2(x) = -d/dx[cot(x)] - 1
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Then, by the Pythagorean Trigonometric identity: cot^2(x) + 1 = csc^2(x). We can rearrange this equation to:
cot^2(x) = csc^2(x) - 1
Realising that -csc^2(x) derivative of cot(x), we can write the above as:
cot^2(x) = -d/dx[cot(x)] - 1
Thanks for watching. Please give me a "thumbs up" if you have found this video helpful.
Please ask me a maths question by commenting below and I will try to help you in future videos.
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