Customers Who Bought All Products | Leetcode 1045 | Crack SQL Interviews in 50 Qs #mysql #leetcode

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Want to crack SQL interviews? Check out our latest video!!!

A 50-questions SQL study plan to ace any interview.
This tutorial will walk you through the solution in easy steps. This is an easy-level question from Leetcode.

Consistency is what transforms average into excellence.
So be consistent & keep Coding💻!!

Timecodes
0:00 - Introduction
0:32 - Question Explanation
1:21 - Understanding Concept with the help of Example
2:36 - Writing SQL Query
3:58 - Explanation of SQL Query
4:57 - Outro

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learnwithchirag
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select c.customer_id
from Customer as c
join Product as p
group by customer_id
having count( distinct c.product_key)=count( distinct p.product_key)

using joins

ranitmandal
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Nice and better solution than using 'where' and subqueries on this problem!

nimbu_
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Here we are equating count(distinct product_key) = (
SELECT count(product_key)
from Product
)
but suppose a customer buy product key 5 and 7 still its count is 2 but product keys given in product table are 5 and 6
So according to question he has not buy all the items??

anonymous_hecklar
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can you please make video on pandas 30 days leetcode QUESTION

aishwaryaarya
visit shbcf.ru