102. Binary Tree Level Order Traversal | JavaScript | BFS | Breath First Search | Easy Explanation

The TC will be O(n*m) where n is the number of total nodes in the tree and m is the length of the level with the maximum number of nodes. For each while condition, we traverse one node at a time which will have TC of O(n), and the shift() operator will have a maximum of m nodes in the queue which will cause the TC of shift() to be O(m). Hence, the total TC is O(nm). Let me know if you have any questions in the comment section below.

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