Fluid 07 : Viscosity and Viscous Force IIT JEE MAINS / NEET (Watch Fluid 08 for Stokes Theorem)

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2)Live Classes and recorded Video Lectures (New, different from those on YouTube)

3)PDF Notes of each class.

4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level.

5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture.

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****Test Series for XI & XII****

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Fluids 05 || Fluid Dynamics 1 || Introduction | Bernoulli's Theorem: JEE MAINS / NEET

Fluid 06 | Applicaion of Bernoulli's Principle -Venturimeter & Speed of efflux- Torricelli's Theorem

Class 11 chap 10 | MECHANICAL PROPERTIES OF FLUIDS 01 | Introduction : Pressure in a Fluid JEE/NEET

Class 11 chap 10 || Fluids 02 || Variation Of Pressure in an Accelerated Fluid JEE MAINS / NEET ||

Class 11 chap 10 || Fluids 03 || Barometer and Manometer and U - Tube problems JEE MAINS /NEET |

Fluids Mechanics 04 || Upthrust and Law Of Floatation for IIT JEE MAINS / JEE ADVANCE / NEET ||

Fluid 09 || SURFACE TENSION 01 : Introduction and Surface Energy IIT JEE MAINS / NEET ||

Fluid 10 || Surface Tension 02 || Excess Pressure inside a Liquid Drop IIT JEE MAINS / NEET ||

Fluid 11 || Surface Tension 03 || CONTACT ANGLE and Shape of Meniscus IIT JEE MAINS / NEET

Fluid 12 || Surface Tension 04 || Capillary Action and Capillary Rise IIT JEE MAINS / NEET ||

[PhysicsWallah]

Live Classes, Video Lectures, Test Series, Lecturewise notes, topicwise DPP, dynamic Exercise and much more on Physicswallah App.



LAKSHYA Batch(2020-21)

Registration Open!!!!

What will you get in the Lakshya Batch?

1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey.

2)Live Classes and recorded Video Lectures (New, different from those on YouTube)

3)PDF Notes of each class.

4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level.

5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture.

6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021)

7)In case you missed a live class, you can see its recording.

8)You can view the videos any number of times.

9)Each chapter will be discussed in detail with all concepts and numericals

10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams.


****Test Series for XI & XII****

We provide you the best test series for Class XI, XII, JEE, NEET chapterwise, which will be scheduled for whole year.
The test series follows very logical sequence of Basic to Advance questions.&
Evaluation of Test and Solution to all the questions at the end of the test.

Class 11 chap 10 | MECHANICAL PROPERTIES OF FLUIDS 01 | Introduction : Pressure in a Fluid JEE/NEET

Class 11 chap 10 || Fluids 02 || Variation Of Pressure in an Accelerated Fluid JEE MAINS / NEET ||

Class 11 chap 10 || Fluids 03 || Barometer and Manometer and U - Tube problems JEE MAINS /NEET |

Fluids Mechanics 04 || Upthrust and Law Of Floatation for IIT JEE MAINS / JEE ADVANCE / NEET ||

Fluids 05 || Fluid Dynamics 1 || Introduction | Bernoulli's Theorem: JEE MAINS / NEET

Fluid 06 | Applicaion of Bernoulli's Principle -Venturimeter & Speed of efflux- Torricelli's Theorem

Fluid 07 : Viscosity and Viscous Force IIT JEE MAINS / NEET (Watch Fluid 08 for Stokes Theorem)

Fluid 08 || Stokes Theorem and Terminal Velocity IIT JEE MAINS / NEET ||

Fluid 09 || SURFACE TENSION 01 : Introduction and Surface Energy IIT JEE MAINS / NEET ||

Fluid 10 || Surface Tension 02 || Excess Pressure inside a Liquid Drop IIT JEE MAINS / NEET ||

Fluid 11 || Surface Tension 03 || CONTACT ANGLE and Shape of Meniscus IIT JEE MAINS / NEET

Fluid 12 || Surface Tension 04 || Capillary Action and Capillary Rise IIT JEE MAINS / NEET ||

[prakhar]

For me definition of happiness is When i can solve sir ka "khoobsurat sawaal "in one go

[oneshotgamer]

At 36:07 the answer : viscous force is 10 N and the external force is 20 N so the net force on boat is (fext.- fv) =10N and F=ma where F = 10N, m=2kg so the acceleration will get 5 m/s². Thanks for this most greatful video sir ☺

[yashvardhansharma]

14:33, Ladies and gentlemen that is y this man is called the God of concept! I don't know if you read comments on these older videos but genuinely phenomenal job sir! Thanks a lot! All the best for the journey!(to you as well reader!)

[Sachin_Meena.]

🙏🙏Ram Ram guruji 🙏🙏

=> F(ext) - F(v) = ma
=> 20 - 10 = 2 × a
=> a = 10 \ 2
=> 5 m/s^2

Thanks a lot sir

[ShubhamSharma-uuyn]

Itni jaldi jaldi KAMAAL KARTE HO PANDEY JI😂😂😂

[samreennaaz]

Hw question:
10 poise = 10-¹ X 10=1 N sec/m²
F=ñAdv/dz= 1 X 1 X 10 X 1=10 N
10 N
Net force=20-10=10 N

a=net force/mass
a=10/2=5m/sec²
ANSWER : [5M/SEC²]

[carguy]

Index:
0:30 inspirational
2:30 start
5:30 velocity gradient
12:00 solid friction revision
15:00 woh lamhe 😄🎤🎼
15:35 viscous force
27:00 solid-liquid friction

[malabikaroy]

The lecture was very good and the answer is 5ms^-2

[avanishmaurya]

Advertisement of other online study platform on his channel confidence level at peak 😊
Btw you are our lifeline sir...we can't imagine our day without you and your lectures 😁

[lokesh]

No other physics Teacher can match your level of Teaching. You are God of Physics as well as online education. You genre of teaching is just Awesome. Congratulations for 3.5 Million subscribers. I really appreciate your hard as well as selfless work of imparting Quality Education and knowledge to the whole generation free of cost. Hats off to you, sir.

[tamannakaushik]

Sir do work according to your wish don't listen anyone how many students agree with me

[popartist_alok]

SOLUTION OF LAST QUESTION 👇👇

friction= -nA*(∆v/∆z)
f=-(10 * 10^ -1)*10
f= -10 N

Net force = 20N -10N=10N

Now, F = ma = 10
Therefore, a = 10/2 = 5m/s²

Thank u sir😊🙏🙏🙇‍♂️

[Kktiwari]

Sir i was too much demotivated today but when i saw the starting of lecture i m felling a different type of energy that makes me motivated

[srishtigupta]

friction= -nA*(∆v/∆z)
f=-(10 * 10^ -1)*10
f= -10 N

Net force = 20N -10N=10N

Now, F = ma = 10
Therefore, a = 10/2 = 5m/s²

Thank u sir😊

[shvenom]

Ans. to last Question:. 5m/s²

My feedback:
It was an amazing lecture, learning basics of viscousity & a slight hints towards Stooke's Law.
In Short, "A Short & Sweet lecture".

[kunal]

Fex=20N
M=2kg
Area=1m²
Height=1m
Cofficient of visocity (eta)=1NS/M²
So we know that f=(eta)(A)(dv/dX)
F=10M
We have studied
Fex-F=ma
20-10=2a
10/2=a
5m/s²=a

[CrazyBoy-ievi]

15:11 haayee vo lmhe yaad aa gye Sir!!! 😅😅😅
Answer for hw question option [b]

[vivekshukla]

35:10 - Answer of homework question is (b) 5m/s². Thanks 😊 sir for the lecture and the motivation.

[Haxislive]

PHYSICS has tought us
1.stress
2.tension
3.pressure
In next video 4.stroke
And new editions in future😂😂😂🤣🤣🤣🤣