A uniform heavy rod of mass \( 20 \mathrm{~kg} \). Cross sectional area \( 0.4 \mathrm{~m}^{2} \...

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A uniform heavy rod of mass \( 20 \mathrm{~kg} \). Cross sectional area \( 0.4 \mathrm{~m}^{2} \) and length \( 20 \mathrm{~m} \) is hanging from a fixed support. Neglecting the lateral contraction, the elongation in the rod due to its own weight is \( x \times 10^{-9} \mathrm{~m} \). The value of \( x \) is : (Given. Youngs modulus \( Y=2 \times 10^{11} \mathrm{Nm}^{-2} \) and \( \left.g=10 \mathrm{~ms}^{-2}\right) \)
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Don't worry guys...ma'am just skipped one basic step which is super usual.... tention while finding elongation is always mgl/2ay 🙏 thank you ma'am🫶

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