JavaScript Problem: Flattening an Array of Sub-arrays

A multi-dimensional array is basically an array of sub-arrays. What if you had such an array and you needed to flatten it; take all of the elements and include them in a single array without any sub-arrays. That is the problem we will solve in this tutorial. The solutions involves recursion and uses other syntax in interesting ways.

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Tutorials referred to in this video:

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[minnuss]

function flatten(arr) {
return [].concat(...arr)
}

[karlstenator]

Can't remember where I learned about this trick, but we can use infinity in flat(). For example;

const myArray = [1, 2, [3, 4], 5, 6, [[7, 8], 9], 10, [[[11], 12], 13]];
let flatArray = myArray.flat(Infinity)
console.log(flatArray); //returns [ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13 ]

[tamilguru]

Sir what happens when we are trying to compare two objects using new keyword. For example,
var str=new String("smith")
var str1 = new String ("smith")
If am trying to compare
C.l(str==str1)//false
C.l(str===str1)//false
Why am getting false here?
What is happening here when we are trying to compare two non-primitive datatype...please explain this sir...

[ErfanHossainShoaib]

const arrayDepth = (arr, currentDepth = 0, maxDepth = 0) => {
for (let e of arr) {
if (Array.isArray(e)) {
maxDepth = arrayDepth(e, currentDepth + 1, Math.max(currentDepth + 1, maxDepth));
}
}
return maxDepth;
}
const arr = [1, 2, 3, [10, 20, [100, 200], 30], [45], 7, [4, [7, [8, [9, [10, [15, [700,



OUTPUT:
7
[1, 2, 3, 10, 20, 100, 200, 30, 45, 7, 4, 7, 8, 9, 10, 15, 700, 80]