CSEC Maths - Gradient, midpoint, equation, length of line examples

In this video I work examples with gradient, midpoint, equation and length of line
For online Classes - Terry David (868-784-2059)

[kellowattentertainment]

Nice video as usual... but please tell me... in the very last example in the video... you multipled everything by 8 except C... C became 3C when both the y value of 3, and the gradient 3/8 (1) were multiplied by 8.... and I'm puzzled as to how that is correct... it seems off to me... please explain

[itstonii.a]

@CSECMathematics  but how when the (3/8)>> when the 8 is being divided so the order of operations would be for you to multiply so that you could cancel out 8 and in doing so anything you do to one side you must also do to the other in which the '8' would be multiplied by the 'C' resulting '8c' like the previous examples you would have given!?😭

[ayannalewis]

2x-4 = -7x+14 9 x = 18/9 =2 y = x-2=2-2 =0 (2, 0)

[britneyramnarine]

Jan exams today you helped Me SO MUCH THANK YOU

[ayannalewis]

Y = 2x+3 gradient= 2 so when x = 4 y = 7

[ayannalewis]

Y = 2x + c when x = 4 y =7 7 =2(4)+ c 7 = 8+C= 7-8=c 7-8=C -1=C y 2x-1

[lovietango]

Sir where you have the finding the midpoint it suppose to 3, 2

[jodilliafigari]

Great vid ..but u made a mistake when you was doing the midpoint instead of putting 2 u put 3 and that offseted the answer .
The answer supposed to be (3, 2)

[elliefromtt]

please explain how you got 3c in the examples its really confusing

[briannadavis]

why does c = 7 ?

please get back to me immediately