Java Programs: How to Find the Second Largest Element #javaprogramming #interviewquestions

Java Programs: How to Find the Second Largest Element | Java Interview Questions and Answers | Java Interview Question | Test Automation Central

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[kundankumargoswami]

this will run for duplicates arr elements also


public class Practice{
public static void main(String arr[]){
int ar[]={50, 50, 32, 4};
int max=Integer.MIN_VALUE;
int
for(int i=0;i<ar.length;i++){
if(ar[i]>max){
secondLargest=max;
max=ar[i];

}
else if(ar[i]>secondLargest && ar[i]!=max){
secondLargest=ar[i];
}

}



}
}

[anubhav.codess]

Sort the array then run loop from right any element smaller than the largest will be second smallest element

[praveenrajdhandapani]

If the array element is duplicated then it will give wrong value.

Eg [6, 7, 7, 8, 8]

[iamnjabulo.]

Sort the array then retrieve the second element at the end of the array by subtracting the array length by 2

[ramrathore]

sir it is failed for n=5
array elements (90 10 20 -5 50)
correct is first declare second with minimum number
second

[arpanganguly]

Arrays
.stream(arr)
.boxed()

.skip(1)
.findFirst()
.get();

[muhammedakcal]

Integer[] arr = {5, 6, 88, 2, 36, 95};
List<Integer> list = Arrays.asList(arr);

Collections.sort(list, Collections.reverseOrder());

if (list.size() < 2) {
throw new should have at least 2 elements.");
}

int secondLargest = list.get(1);
System.out.println("Second largest element: " + secondLargest); //88
}
}