#13 REAL ANALYSIS TEST SERIES-13 | Uniform Continuous in Hindi | Basic Concept of Uniform Continuity

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This video lecture i will provide Real Analysis Test series for CSIR NET/GATE/IIT JAM /TIFR/NBHM/OTHER EXAMINATION
I will try taken daily live classes at 8: 30 pm with full solution .

Real Analysis Test Series-13 | UNIFORM CONTINUOUS
DOWNLOAD PDF (27/09/2019)-UNIFORM CONTINUOUS
Related topic:
1.Basic Concept of uniform continuous
2. Definition of uniform continuous
6.10 solve problem
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Mai aap ki video tab se Delta hu jab aap start kiye the

akarshroy
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sir please continue this live test series i really need it and thank u so much sir

nehagautam
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Sir how you used limit criteria and justified that limit exist finitely for √x? Since graph of √x is parallel to x axis uniform continuity occurs. But how it got matched by using limit criterion?

sanjithar
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While veryfing f(x)=1/x on (0, 1)is UC open interval was given
how do we take limit x tends to 0 thank you

tirapathireddy
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Sir ....1st ques ka answer b, d dono hone chahiye?

kirtisingla
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Function of bounded Variation b explain kraye

sajidmunir
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1st ques k D option me interval break krna hoga...[0, 1]union[1, ~) me...tab derivative bounded ho jaega..then uc hoga

kirtisingla
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I have completed my csir net course.... And now i m working only on

nehagautam
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Actually u r taking h and f same bt the relation is h(x)=f(x)-x

baljinderchahal
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Sir good morning
Ye tarka Accha to hai
But aap hello hi krte rhenge to concentrate ni ho payega topic pe
Ye Mera suggestions hai bus
Thanks

akarshroy
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Sir in que. 7 when u take f(x)-x apne x to subtract kiya nhi function se .i think ap glt kr rhe ho

baljinderchahal
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Sir Maine 4 questions telegraph kiya hai please sir discuss

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