HSC Maths Ext2 - Complex Numbers - Solving equations using De Moivre's Theorem

Welcome to my HSC 4 Unit maths: Complex Numbers series. In this video we see an example on how to use De Moivre's Theorem to solve equations. This example is of the form Az^4+Bz^3+Cz^2+Bz+A = 0, which is a symmetric equation. The next video in the complex numbers series shows an alternate method to solve these equations, even if the the solutions are not complex.

Be sure to SUBSCRIBE for more videos in the future.

[Mathsalldayerrday]

LOVE your videos don't stop what you're doing because it really helps! Thanks 

[BeMedic]

Shouldn't z^n = r^n(cos[na] + isin[na]), where r is the modulus, a is the angle?

Therefore, z^n = cos[na] + isin[na] is true if and only if
r = 1.