90 Degree Counter Clock Wise Rotation About Any Arbitrary Point

#combinedtransformations #Simpletransformations #CoordinateTransformations #SpatialGeometricTransformations #GCSE #Rotation #Reflection #transformations #Translation #2dGeometry #AnilKumar #GlobalMathInstitute #transformations_GCSE

[zengance]

I struggled with this the day before a quiz and a friend recommended this to me, thanks!

[sharvendranair]

this man has taught me more then my teachers have for this

[MarciaArleneDebra]

After watching your videos, I realize the dangers of technology. Your presentation has provided an understanding of what happens when you do a rotation from any point. Using technology, you are shown what to do, but you are not told why. Yours is my kind of teaching.

[israfahad]

I had a literal mental crying breakdown because of this topic XD. But thanks to you, I've understood the entire topic :D. I have an upcoming IGCSE exam in a few months. So, can you plz make a video to show how to describe transformations (using only rotations)? Example: Describe the transformation that maps Triangle A onto Triangle B?

[aoaoai]

This was really helpful for my exam!!!
Thank you so much!
Because I have a test today

[qilinxie]

Thank you so much! Your video explains better than any other videos I found you are the best thank u save my life!

[eriliatrisyia]

Omg dude u saved my life, my useless brother cant even help me but again thank you so much

[ARD]

Thank you soooo much for this. I am terrible and math and struggle to learn it but you helped me a lot. Really helped me pass my math test. Thank you again

[jawhi]

Thank you! This helped me on my homework.

[huyanhle]

Rotation of a point or a graph -90/+90 degree or 180 degree at any center point without needing to draw any graph.

Formula 1: Rotation of a graph 90 degree anti-clockwise (or counter-clockwise) about origin (0, 0)
(X, Y) ==> (-Y, X)


Formua 2: Rotation of a graph 90 degree clockwise (or 270 degree clockwise) about origin (0, 0)
(X, Y) ==> (Y, -X)


Formula 3: Rotation of a graph 180 degree anti-clockwise (or counter-clockwise) about origin (0, 0)
(X, Y) ==> (-X, -Y)
To do mathematical calculation you need to do 3 following steps.
(Note: (Xp, Yp) is the name of center-point of rotaion of the graph, (not X*p, Y*p))


Step 1: Move/Shift the graph to origin (0, 0)
(X - Xp, Y - Yp) Formula 4
(Xp and Yp are just names (not X*p, Y*p))


Step 2: Use according Formula 1, 2 or 3 for rotational graph -90 degree, 90 degree or 180 dregree to rotationally solve the this step


Step 3: Move/Shift the graph back to the rotaional center-point with formula below
(X + Xp, Y + Yp) Formula 5
(Xp and Yp are just names (not X*p, Y*p))

I am using example in this video clip to mathematically solve the method above


Example: Rotate the triangle graph of points A(-1, 2), B(-4, 4) and C(-4, 0) 90 degree counter-clockwise about the center-point P(Xp, Yp) = (1, 2)


Solve:
Step 1: Move/Shift the graph to origin (0, 0)
(X - Xp, Y - Yp)
A(-1, 2) ==> Ao(-1 - 1, 2 - 2) (Ao is just a name (not A*o))
= Ao(-2, 0)
B(-4, 4) ==> Bo(-4 - 1, 4 - 2) (Bo is just a name (not B*o))
= Bo(-5, 2)
C(-4, 0) ==> Co(-4 - 1, 0 - 2) (Co is just a name (not C*o))
= Co(-5, -2)

Step 2: Use according Formulae 1, 2 or 3 for rotational graph -90 degree, 90 degree or 180 dregree to rotationally solve the this step.
In this step, the question says rotate 90 degree counter-clockwise. Hence, we use "Formula 1"
That is (X, Y) ==> (-Y, X)
Ao(-2, 0) ==> A'(0, -2)
Bo(-5, 2) ==> B'(-2, -5)
Co(-5, -2) ==> C'(2, -5)

Step 3: Move/Shift the graph back to the rotaional center-point with formula below
(X + Xp, Y + Yp)
A'(0, -2) ==> A''( 0 + 1, -2 + 2)
= A''(1, 0)
B'(-2, -5) ==> B''(-2 + 1, -5 + 2)
= B''(-1, -3)
C'(2, -5) ==> C''(2 + 1, -5 + 2)
= C''(3, -3)

[pencil]

Not the hero we needed but the hero we deserved



Thanks sir

[destipw]

This man save me, i watched this a day before my test and i got 2nd in my class

[zohaibmohammed]

Thanks again.You are really a very noble person.

[johntitone]

Excellent. I just suggest you label the points for the image.

[chiwa_sedu]

I'm finally able to solve the question thanks to your video.

[munish]

Very beautifully explained. Thank you so much.

[kapardimathclasses]

Co ordinates of original triangles are with respect to (0, 0). Co-ordinates new triangle are with respect to point P so we need to find coordinate of new triangle about (0, 0) then we need to fix the position of new triangle. Please check

[xkvhamid]

I m a teacher i like ur method tnx u sir

[SPiiCY]

very clear instructions to follow. made the task easy to do now. thank you,

[tala]

Thank you!! I have a test tomorrow and this helped so much!