Limit Characters - Like Twitter! (Swift in Xcode)

Thanks for watching! Be sure to subscribe and recommend future videos. :)

Snapchat! - archetapp

[Nina-qtnb]

Will not work if the user copies and pastes text into the field.

[HakkiKonu]

Hey Jared, I love your tuts. Please keep on :)

[dubelan]

Instead of using:
count(myTextField)

do:

[anthonyaustralia]

hi jared
i created:
5 buttons :
buttonA
buttonB
buttonC
buttonD
buttonE

the buttons (buttonB buttonC buttonD buttonE) are hidden

the play is:
i click on buttonA, buttonB will appear
i click on buttonB, buttonC will appear
i click on buttonC, buttonD will appear
i click on buttonD, buttonE will appear

the problem is:
i click buttonC, buttonD will appear, but the user can't see it, bcz its outside the screen size.

what i want to do is, when i click on buttonC, the screen automatically slide down to show buttonD at the bottom of the screen, so i can click on buttonD, and the screen will slide down again to show buttonE :)

thanks

[djskywalkerremix]

Great video Jared!! Any chance you could do a video on how to record video with the built in camera?

What would also be great is how to save a retrieve this newly recorded video to/form Parse.

One more great video would be how to enable editing picture controls when taking a picture with the UIImagePickerController.

Leep up the great vids :)

[DaviNasta]

Hi Jared! Great video! I've got an issue though. If I try to connect a label that tells me how many characters are left to type I get an error off by one when I type the first character and the last one. Do you know what the issue could be? Thanks!

[richardgomez]

shouldcharterinrange not available in swift 4 can you update
thanks

[TahaS]

I use one more ShouldChangeCharactersIn method for blocking some characters. For this reason, I can't use this. How can I mix two of them ?

[slammerw]

Hey, can you help or do a video on character limit on strings for a label. Thanks.

[khungsokhim]

error Message: "Cannot invoke 'count' with an argument list of type '(String)'"
How to fix it Mr.Jared Devidson ?

[michaelwitt]

Please help... My textfield is set to only accept number using the number pad keyboard. I have followed this video repeatedly but I keep getting an error in the code that says "Cannot invoke 'count' with an argument list type of '(String)?'

My goal is to have a textfield that only accepts two digits for the user's age. The user will only have the option to use the number pad to input their age. Thanks

[kantarlin]

Hey Jared, seems like i cant delete the input once I reach the limit. any clues how can i fix that? thank you

[richardgomez]

hi nice tutorial need help something is not right with my code
count is giving me an error
here is my code

im using xcode 8.2.1


@IBAction func tipobegin(_ sender: Any) {


func TextField(TextField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {

if range.length + range.location > (tipo.text!.characters.count) {
return false

}
let newLength = (tipo.text!.characters.count) + (string.characters.count) - range.length
return newLength <= 5

}

[opensourcerer]

Have you submitten any apps to AppStore?:)

[bilalakram]

what about swift 3? this aint working :/

[SpellOdyssey]

what about swift 3 cuz this code doesn't run :/

[emreciftci]

User copy and paste 50character text four times?

[JulianAilemen_i]

working code as of today 5th july 2017

func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {

let text = username.text!;

let newlength = text.characters.count + string.characters.count;

return newlength <= 5;

}

[pravalikad]

This logic won't work for copy and pasting.

[Bennyclay]

this code working as of today 26/5/2017

func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {

let currentCharacterCount = ?? 0
if (range.length + range.location > currentCharacterCount){
return false
}
let newLength = currentCharacterCount + string.characters.count - range.length
return newLength <= 5
}