Student’s t-test | Difference between two mean method (Independent samples)| Small Sample Test

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In this video, we will solve an example of second method of t-test (small sample test) i.e. Test of significance of difference between two mean (Independent samples) and we’ll also learn how to use T- table.
T test is used in hypothesis testing for small samples.

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There is a mistake in the video:
When we are using <, > signs in H1 then observe the value at 10% and not at 1%. Sorry for the inconvenience.

statisticsforall
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channel is growing....keep it up...keep uploading these beautifully explained videos 🙌

dollysharma
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Thanks x100 madam
❤️❤️
Crystal clear

myworld
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S = 2.14
Diff 3.12
SE 1.19
Tc 2.62
Tt 3.106 at 1%
Ho is accepted

hamzamansuri
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thankuu so much mam
really to teach superb
thanku mam from may heart❤

SunitaSharma-nwms
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Hello mam your video was very for last preparation of my test but I want to ask one question how can we identify whether it's a two tailed test or one tailed test in independent t-test

prathasaxena
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T, c = 2.71 then Tc > Tt H0 is rejected

hforheadshot
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it Is rejected ? Tt=1.796 < Tc 2.62 is this correct?

aastha.rajput
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Mam mera sample 60 he to vo table alag he kya

sangitabhargave
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Question me level of significance 5% diya ho and more than word ho
(H1:μ1>μ2 hypothesis nikal raha ho)
To fir t-chart mese value 1% ki leni he ya 5% ki?

krenilsojitra
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Mam b. Sc 4th sam k video plz bcz mera 3rd ka exam hone wla h

NOTGREATERFF
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Mam please aapne jo question diya he uska answer bataiye na mam please 🙏🏻🙏🏻🙏🏻

ektachauhan
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Tc = 2.63 and Tt = 3.106 @ 1% Significance
Then Ho is accepted
Is this Right?

rajmalhotra
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you mentioned an incorrect formula to calculate SE. It should be under the root of SD1 square divided by n1 + under the root of SD2square divided by n2. Wasted so much time 😒

UnscriptedTales
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Solution: que 1:
D.F 11
T cal = 2.201
Ho is accepted

animesaga
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it will be better if the language was english

ponoanelimpho