Painter Partition Problem | Google Interview Question | Binary Search | InterviewBit Problem

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Hi,

This is the tenth video of our playlist named "InterviewBit Problems and Solutions"

Hope you will like it.

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Комментарии
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Thanks bro, watched till half and got the green tick :-D

binarybeast
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This same approach is also done for minimum pages problem which is asked several times for big tech companies

Godzilla-yu
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Thank you very much bro for this wonderful explanation. I wasted my whole one day to solve this problem using recursion and dp and not able to solve leaving me demotivated. Thanks buddy for this wonderful explanation

sunidhi_ashish
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Bhai
Best explanation. Thanks a ton!!

jashanbansal
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Good explanation bro.. it's crystal clear ❤️

bhaswanthreddy
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Thank for the video. Helped a lot! I had a question. what if we were asked the same question but only this time painter can paint any board he likes, i.e there's NO constraint of him picking the adjacent board.
Thanks again!

yashpaste
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Nice, but how it was 40 lower bound at first

secularph
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@9:30 Why is the "ans" variable not getting updated to "ans=high" ?

swatirauniyar
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Thanks a lot for the explanation. But I have a small clarification, the first mid value should have beem 54 right? [ (40+69)/2 ]

IndiaBornLivingAbroad
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Thank you for the amazing explanation!

arhankundu
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Really helpful dude thanks a lot.... share playlist or questions for interview preparation in pdf file

YashwanthReddy-zrnk
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Isn’t the minimum answer 250? You assign the first and last board to the first painter whereas the second and third board to the second painter.

riyadSDSL
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haha thanks !! It was helpful !! And great Explanation

vaidyamvikramkumar
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Thank you so much for your resourceful video!!

bmbharathh
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i think in the end it will become 60 to 59 not 59 to 58 correct me if i am wrong

aayush
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Thanks a lot Vivek Sir, do u give private tuitions?

simransinha
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Sorry bro didn't understand anything.
Edited: after reading GFG and other posts, and watching your video again I got a better idea. Thank you.

unav-daily
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