Object.assign() Method : Object Oriented Programming in JavaScript Series - Part 7

[dragonniteIV]

Very well explained! No nonsense and just straight to the point. Thank you sir!

[shivamsa]

making javascript easy.
learning by examples approach instead of raw theory makes is far better.
excellent content.

[HakanGalip]

Thanks a lot for this wonderful series.

[velmurugan.personel]

I spend more time in your channel and i suggest to all my colleague about your channel...Thanks man...

[artemipatev]

Great tutorials! Thank you so much!!!!

[abhiabhang]

Hey genius, I implement it, Its work fine, Thanks for sharing the videoes.

[joshrochon]

Hey so instead of Toyota you should give the break() method to Ford

[swetlinasatpathy]

till this video I found the tutorials quite in-depth and easy to understand. Thanks for all your effort and time.
do you have any html5 and reactjs tutorial ?

[oonurgulay]

Hi, first of all, I am very thankful for your tutorials, but I am little bit confused about shallow copy explanation. As I know, shallow means not copy of object, it means sharing same local memory and has same reference, so if you change one of them object, other one will be affected. But if you copy object with Object.assign and then you add new method or property to object, the other object will not be affected.
It is like Deep Copy, isn't it?

[yadusolparterre]

Didn't you forget a return statement in the last function?

[baturalkan]

4:00, actually Object.assign() doesnt make the shallow copy, instead makes the deep copy with below exception, please check this MDN example;
(If the source value is a reference to an object, it only copies the reference value.)

let obj1 = { a: 0, b: { c: 0}};

let obj2 = Object.assign({}, obj1);
// { "a": 0, "b": { "c": 0}}

obj1.a = 1;
// { "a": 1, "b": { "c": 0}}
// { "a": 0, "b": { "c": 0}}

obj2.a = 2;
// { "a": 1, "b": { "c": 0}}
// { "a": 2, "b": { "c": 0}}

obj2.b.c = 3;
// { "a": 1, "b": { "c": 3}}
// { "a": 2, "b": { "c": 3}}

[Atif]

Hello, you said that prototype methods don't get copied but I tried the below code and type() method is in both objects, vitz and toyota.
Why is that so? It should not be present in vitz object, right?

let toyota = {
  drive() {
    return 'driving toyota';
  }
};

toyota.prototype = {
  type() {
    return 'Sedan';
  }
}

let vitz = Object.assign({}, toyota);
console.dir(vitz);
console.dir(toyota);

[mykolavoinikov]

Is it a good practice to use Object.assign method in constructor?

[jainshilpi]

Can u pls exaplain shallow and deep copy in little detail?

[whome]

I thought in objects it needed to be drive: function(){},

[martinbozinovski]

check this out..
object.assign( [ ], obj ). Magic :). Not a shallow copy right? Or am i just writing rubbish?