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`(tan theta)/(sec theta -1)+ (tan theta)/(sec theta +1) = 2 cosec\ theta`
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`(tan theta)/(sec theta -1)+ (tan theta)/(sec theta +1) = 2 cosec\ theta`
tan theta+sec theta-1/tan theta-sec theta+1=1+sintheta/costheta
Prove (tan@+sec@-1)÷(tan@-sec@+1)= (1+sin@)÷ cos@
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tan theta/1-cot theta + cot theta/1-tan theta= 1+ sec theta cosec theta
`(tan theta)/(sec theta -1)+ (tan theta)/(sec theta +1) = 2 cosec\ theta`
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(sin theta-cosec theta)(cos theta-sec theta)=1/tan theta+cot theta
`(tan theta+sectheta-1)/(tantheta - sec theta +1)=(1+sintheta)/(costheta)`
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`(tantheta)/(sectheta+1)+(sectheta+1)/(tantheta)=2cosectheta`
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Prove that sec theta +tan theta-1/tan theta-sec theta+1=cos theta/1-sin theta
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sec theta - tan theta/ sec theta + tan theta = 1-2 sec theta tan theta +2tan^2 theta
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