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Using Double-Angle Identities to Verify Other Trig Identities (MathAngel369)

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Verifying Trig Identities Using the Double-Angle trig identities (MathAngel369)
In this discussion, we are going to verify trigonometric identities using the double-angle identities.
Here is an outline of this discussion:
(Skip ahead if you like)
Verify that (1-cos2x)/sin2x = tanx
(Skip to 0:16)
Verify that sin2x = 2tanx/(1+ tan^2x)
(Skip to 3:08)
Let’s begin!
Verify that (1-cos2x)/sin2x
We begin with the left-hand side of the equation and slowly manipulate it until it looks like the right-hand side.
LHS
= (1-cos2x)/sin2x
= (1-(1-2sin^2x)) / 2sinxcosx
= (1-1+2sin^2x) / 2sinxcosx
= 2sin^2x / 2sinxcosx
= sinx / cosx
= tanx
= RHS
Verify that sin2x = 2tanx/(1+ tan^2x)
This time, let us begin with the right-hand side and slowly manipulate it until it looks like the left-hand side.
RHS
= 2tanx/(1+ tan^2x)
= (2sinx / cosx )/ (sec^2x)
= (2sinx / cosx )/ (1 / cos^2x)
= 2sinxcos^2x / cosx
= 2sinxcosx
= sin2x
= LHS
We are done!
I hope that I can assist you in your math journey!
Sincerely,
➕MathAngel369➕
🎥 Suggested Video and Playlist:
Video: Proving the Double-Angle Trig Identities
Playlist: Proving/Verifying and Using Trig Identities
📝Blog Post:
Read my blog post associated with this video:
🔑 Math Course:
Practice is the key! If you would like to become an expert in trig identities, consider taking my math course.
You can preview about 10 minutes of the course for free before purchasing.
Proving/Verifying and Using Trig Identities
For a list of all my courses, go to my website:
Youtube: MathAngel369
Facebook: @mathangel369
Instagram: @mathangel369
#MathAngel369 #TrigIdentities #Trigonometry
In this discussion, we are going to verify trigonometric identities using the double-angle identities.
Here is an outline of this discussion:
(Skip ahead if you like)
Verify that (1-cos2x)/sin2x = tanx
(Skip to 0:16)
Verify that sin2x = 2tanx/(1+ tan^2x)
(Skip to 3:08)
Let’s begin!
Verify that (1-cos2x)/sin2x
We begin with the left-hand side of the equation and slowly manipulate it until it looks like the right-hand side.
LHS
= (1-cos2x)/sin2x
= (1-(1-2sin^2x)) / 2sinxcosx
= (1-1+2sin^2x) / 2sinxcosx
= 2sin^2x / 2sinxcosx
= sinx / cosx
= tanx
= RHS
Verify that sin2x = 2tanx/(1+ tan^2x)
This time, let us begin with the right-hand side and slowly manipulate it until it looks like the left-hand side.
RHS
= 2tanx/(1+ tan^2x)
= (2sinx / cosx )/ (sec^2x)
= (2sinx / cosx )/ (1 / cos^2x)
= 2sinxcos^2x / cosx
= 2sinxcosx
= sin2x
= LHS
We are done!
I hope that I can assist you in your math journey!
Sincerely,
➕MathAngel369➕
🎥 Suggested Video and Playlist:
Video: Proving the Double-Angle Trig Identities
Playlist: Proving/Verifying and Using Trig Identities
📝Blog Post:
Read my blog post associated with this video:
🔑 Math Course:
Practice is the key! If you would like to become an expert in trig identities, consider taking my math course.
You can preview about 10 minutes of the course for free before purchasing.
Proving/Verifying and Using Trig Identities
For a list of all my courses, go to my website:
Youtube: MathAngel369
Facebook: @mathangel369
Instagram: @mathangel369
#MathAngel369 #TrigIdentities #Trigonometry