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If x = acosθ + bsinθ and y = asinθ - bcosθ then prove that y² d²y/dx² - x dy/dx + y = 0
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#math #calculus
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#math #calculus
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If (x/asinθ-y/bcosθ)=1 and (x/acosθ+y/bsinθ)=1, prove that (x^2/a^2+y^2/b^2)=2 . PU
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