If x = acosθ + bsinθ and y = asinθ - bcosθ then prove that y² d²y/dx² - x dy/dx + y = 0

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If x=acosθ+bsinθ and y=asinθ−bcosθ then prove that y2dx2d2y​−xdx/dy​+y=0.
If acosθ−bsinθ=x and asinθ+bcosθ=y
If x = a cos theta + b sin theta and y =asin theta-b cos theta, then prove that y^2 (d^2y)/(dx^2)-x(dy)/(dx)+y=0.
If x = a cos θ + b sin θ and y = a sin θ - b cos θ, then prove that : y2d2y/dx2 - xdy/dx + y = 0.
If x = acosθ + bsinθ and y = asinθ - bcosθ then prove that y² d²y/dx² -x dy/dx + y = 0
#math #calculus
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Thanku so much sir .. ❤ very easy explanation❤

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