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Show that `|[a,b,c],[a^2,b^2,c^2],[a^3,b^3,c^3]|=abc(a-b)(b-c)(c-a)`
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Show that `|[a,b,c],[a^2,b^2,c^2],[a^3,b^3,c^3]|=abc(a-b)(b-c)(c-a)`
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Mathematics Solution 'a+b+c=15, a²+b²+c²=83, ab+bc+ca=?'
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DÉMONTRER QUE pour tous réels a, b et c / a+b+c=0, a^3+b^3+c^3=3abc.
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To prove a3 + b3 + c3 - 3abc = (a + b + c)(a2 + b2 + c2 - ab - bc - ac) class 9th
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If a+b+c=15 and a^2+b^2+c^2=83 find the value of a^3+b^3+c^3-3abc. Polynomials | class 9 maths |
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R S Agrawal 3G Class 9 Prove a^3+b^3+c^3 - 3abc = 1/2 (a+b+c){(a-b)^2 + (b-c)^2 + (c-a)^2} Hindi Me
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Prove that : `(a+b)^3+(b+c)^3+(c+a)^3-3(a+b)(b+c)(c+a)=2(a^3+b^3+c^3-3a b c)`
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