DETERMINISTIC FINITE AUTOMATA (DFA) EXAMPLE - 2 (STRINGS ENDS WITH) IN AUTOMATA THEORY || TOC

DETERMINISTIC FINITE AUTOMATA (DFA) EXAMPLE - 2
Design DFA which accepts all strings over given alphabet which ends with given substring.

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[botzaifa]

In Question 2 (11:51) : What if we end q2 to a self loop 0. Even that gives the desired results and is a valid string. Right?

[MohammedSohail]

man i have exam at 10am today, glad I found your channel in time, perfect explanation

[naveenbanoth]

Sir at final state can we take loop in 1, 0 when ends 10 condition

[danceflorr]

sir.. why can't we give 0 as the self loop to the final state "q2". It is also satisfying 10010 string....???? (check 11:50 )

[manatelugodichannel]

for every dfa their is more than one pls explain atleast 2 possibilities...so that we can understand easly

[sarkersaadahmed]

4:35 if you left the 1 at q1, it would still be q1 correcT?

[sarkersaadahmed]

3:07 why dont you go back to q0 if the input was 0?

[PrasadPutta-no]

can we create q2 to dead state 0 1 we can do like that

[adhithya]

Sir can we take Instead of taking transition of q2 to q0, can we place a self loop to q2 has 0

[naveen.bnaveen.b]

can we create a self loop 0 to the state
Q2

[mohanchandra]

Can we give self loop of 0, 1 on initial state

[kbvrama]

how q0 on 1 become q0 need clarity saradhi gaaru (10)

[ghoshentertainment]

If 1001 then q2 will be the final state.
Here q3 is final state, is this correct?

[technologyworld]

Sir, I end (0)
dead state is not use

[zooheb]

You forgot to remove self transition from the state q1

[kartikkhandelwal]

sir.. why can't we give 0 as the self loop to the final state "q2". It is also satisfying 10010 string....???? (check 11:50 )