Introduction to mmwave sensing : FMCW Radars

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Credits: Texas Instruments
This for educational purpose.
This video is made TI.
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Very nice teacher makes me understand the FMCW from scratch, thank you a ton

bjnidmc
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Great teacher! Step by step lead me running through the dark tunnel. Thank you!

andreaskunze
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You're the only guy who made this easy on YouTube

Andratos
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Thanks very much, you saved much time for me in order to search for these concepts

omaralngar
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Great video, this really helped me alot in understanding the FMCW Radar concept and processing. Thank you very much!

autaulti
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Very informative series and pedagogical approach, good description of basic concepts.

pcirrus
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Answer at 14.40: Chirp A has better frequency resolution than Chirp B, of course. On the other hand, two objects with the same Δd will result in a larger frequency separation in Chirp B because of the higher slope rate, S (see S*τ in 7.20). So, Chirp B has lower frequency resolution than Chirp A but the IF frequencies of the two objects are farther apart between each other in the case of Chirp B than in Chirp A. The net result is that the range resolution is a function only of bandwidth and the two Chirps will have the same range resolution.

Leonardo-fmfj
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The best and great informative video for radar researchers.. Explanation is excellent. Neat English.👏👏👏👏👏

kaluvanhariharan
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Very educative, simplified, teaching of such a novel high tech

NamdeoPatil
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Thank you very much for very sensible presentation of the material.

ashotyayloyan
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Thank you sir, very nice explanation. One of the best tutorial

brmkor
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Excellent presentation Sandeep. Small technical details on Fourier transform computation and resolution are valuable and needed in successful implementation.

gushant
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Awesome Videos! This is an excellent explaination and tutorial!

tarkeshpande
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This is very useful video for understanding FMCW Radar. Thank you.

zqqchhw
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Thank you for this interesting video with a lot of info!

athuran
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Thanks a lot for this video. I just have some comments:
Minute 13:50. In the plot it is written S = BTc, but since it is the slope it should be S = B/Tc.
Minute 20:35 d_res = c/2B. This means that d_res is conversely proportional to Bandwidth. This implies that, by increasing the Bandwidth reduces de d_res. However in the blue rectangle it is written that Larger Chirp Bandwidth leads to better range resolution.

johangoethe
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Shouldn't Fs > 2 x IF_max to satisfy Nyquist sampling?

ayniliantechtechnologies
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Very good and interesting video, well explained. I was kind of confused by the derivation in slide 17 because of the mentioned formula S=BTc, which is incorrect. It should be S=B/Tc.

Tommiegrand
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Excellent stuff! But, at 9:35, you have slight error in the diagram of "Multiple tones in the IF signal"; Lower tone should be longer than one above, and middle one longer than last upper one. Not a big deal, but people who experimenting with some modules may find it confusing. I am waiting my "cheap" $6US 24 GHz module to arrive... then fun can begin. Thanks.

MilanKarakas
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Thank you very much for the tutorial!
I have a question on page 13. Shouldn't the 3 f of the IF signal (the horizontal lines) start at the time each of them is received, and end at the same time (where Tx ends)? Why are they all lined up at the beginning? In my understanding it should be like a upstair staircase. Bottom line should be the longest as it's the closet object Rx and receives the earliest. And such for the top two lines... Or am I understanding it wrong? Thank you!

michellecheng