How to fix SyntaxError: invalid syntax in if var != None: use var is not Non... in Python

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We're excited to share with you our newest video, "How to solve SyntaxError: invalid syntax in if var != None: use var is not None instead. in Python". 🎥 This series is meticulously designed to arm you with knowledge 🧠 and skills 🛠️ to overcome frequent coding challenges.

Today, we will decipher 🔎 and resolve a common error faced by Python coders: the bit hard to solve SyntaxError: invalid syntax in if var != None: use var is not None instead.. Here is a snapshot of the code of the video:

Troubling Scenario: ❗️

var = 1
if var != None:
print("var is not None")

Unwanted Result: 🚫
SyntaxError: invalid syntax in if var != None: use var is not None instead.

Effective Resolution: ✔️

var = 1
if var is not None:
print("var is not None")

Desired Output: 🏁
var is not None

In this detailed walkthrough, we will illuminate 💡 the underlying cause of this error, and offer a comprehensive explanation: Code1 has a syntax error because it uses "!=" to compare with None. Python prefers "is not" for None checks. Code2 corrects this by using "if var is not None". 🎯

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