Class 12 Ex 7.2 Q5,6 Math | Chapter7 Class12 Math | Integration | Ex 7.2 Q5,6 Class 12 Math

Class 12 Math Chapter7 Ex7.2 Q5
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Class 12 Math Integral
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Ex 7.2 Q5 Class 12 Math Integration | Q5 Ex 7.2 Class 12 Math |
Class 12 Math's Ex 7.2 Q5
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[mairasingh-bbwb]

ax+b=t
dx=dt/a
I=integration of sin (ax+b) cos(ax+b)
Let put (ax+b) =t
=integeration of sint. Cost dt/a
1/a integeration of sint. cost. dt/a
Therefore we know that sin 2Q=2×sinQ×cosQ
cosQ×sinQ=sin2Q/2
1/a integration sint×cost×dt
1/a integeration sin2Q/2dt
Therefore integeration of sinxdx =-cosx+c
=1/2a [-cos2t/2]+c
=-1/4a cos(2Q) +c
=-1/4a cos[2(ax+b) ]+c

[umasharma]

Sir, 5th question ka alag answer aa rha ha book me.

[sma]

2:14
People tend to forget that integration has multiple answers possible.

[VinayYadav-vnrl]

Sir plz class 12 ki math ko thoda fast kare... Mere class ke students aapki ki hi videos dekhte h aur teacher ne bhi kha ki inn videos ko dekhoge to 12th me maths 100% result aayega

[VISHALFF-k]

सर आपके पढ़ाने का तरीका
पूरा दिमाग में आ जाता है।

[anshrohatgi]

Sir in 5th question,

We have to take,
(ax+b)=t
dx = dt/a

:we will get further by solving,
1/a | sint cost dt, then we will divide and multiply the equation by 2 which will make,

1/2a | 2sintcost dt
We will take 2sintcost = sin2t and then integrate the function
We get,

=1/2a (-cos2t/2)
=1/-4a[cos2(ax+b)] ↔ Anshwer

[shambhavi]

I pray to god to give you all the happiness of the world. You made 240+ videos for a single chapter which requires so much of effort ! Thank you so much Sir ❤

[nikitakushwaha]

Thank uh sir for explaining the questions so easily 🙏

[lancelotff]

Sir aapne bola thank you students for watching your channel Nexa Classes

To Phir ID & PASSWORD lao jaldi jaldi mujhe bhi upload karne he gaming vodeos

[murari]

Answer of question no 5. is wrong.Please improve that sir so that any one can learn correct.

[dhanushdhanushkumar]

Tq so much for learning sir ♥️♥️♥️♥️♥️

[vishal_.]

Sir denominator me 2 ki jagah 4 aayega

[dhairyaveersingh]

Integrals can have many answers. But, to all who are wondering about the answer of question 5 .
Divide and multiply the term by 2 .
Inside there will be 2 Sin(ax+b).Cos(ax+b)dx which can be written as Sin 2(ax+b) which is Sin (2ax+2b). Its integration will be -Cos(2ax+b) / 2a + c
Outside the bracket is 1/2 . then multiplying we will get -Cos(2ax+2b) / 4a + c.
Hope you all get it. 😊

[AnkushPaul]

Guruji questions no. 5 ka ans NCERT me ye nhi hai ..I am confused

[himanshusingh]

For Simple Calculation We have to put ax+b=t^2 so we will get the answer 2/3a (ax+b)^3/2 + c

[PiyushKumar-yipo]

Sir 5th wale ka ans -1/2a cos²(ax+b) ho shakta hai kya agar ham cos(ax+b) = t le??

[Jugnu]

Hello sir
I have a humble request you to check this question properly 😊

[avatarvilen]

Sir plzzz ch6 k bhi exercise wise one shot daaldijiye plzzz sir🙏🙏🙏

[md.faishal]

Sir question no 5 ka answer wrong h according to the ncert
Plzzzz recheck it

[SonuYadav]

Sir can we do ques 6 by normal integration