#11 Understanding Else if and Nested If | Java Tutorial Series 📚 in Tamil | EMC Academy

In this episode of our Java Tutorial Series, we delve into the intricacies of the 'else if' statement and explore the concept of nested 'if' statements. Mastering these fundamental control structures is essential for any Java programmer aiming to build robust and efficient applications. Join us at EMC Academy as we demystify these concepts, providing clear explanations and practical examples to deepen your understanding of conditional logic in Java. Whether you're a beginner or looking to brush up your skills, this tutorial will equip you with the knowledge needed to navigate through complex decision-making scenarios in your Java projects. Dive into the world of conditional statements with us and elevate your Java programming expertise!

Java in Tamil.

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[akilanxll-a]

7:15 class Main {
public static void main(String[] args) {
int score=100;
if(score>=35&&score<60){
System.out.println("video game");
}
else if(score>=60&&score<90){
System.out.println("i phone");
}
else if (score>=90){
System.out.println("MAC BOOK");
}
}
}

[pedrikoespaniel]

bro nejama sollanumna neenga kudukara example thaan bro intha manjal dappa tumbler nu daily use pandra things ah vachu easy ah sollitharathu thaan bro mathatha channels la paatha full ah language ah apdiye avunga understanding la irunthu solluvanga ana new learners ku understand panna kastama irukum ungaloda antha comparison and examples irukarathulaye best and worth ana content bro learn pannika

[AkalyaNatarajan-tk]

Anna file link ella anna description la

[BenielLap]

5:35

import java.util.Scanner;
class hello{
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.print("Enter your mark : ");
int score = sc.nextInt();
if (score>=90){
System.out.print("I can get MacBook Pro");
}
else if (score>=60){
System.out.print("I can get Iphone");
}
else if (score>=35){
System.out.print("I can get Video game");
}
else{

}
}
}

[Lala_]

4:15
import java.util.Scanner;
public class Sanjay{
public static void main(String[] args) {

int mark =30;

if(mark>=35 && mark<=59) {
System.out.println(" video game");
}
else if(mark>=60 && mark<=89) {
System.out.println(" iphone");
}
else if(mark>=90 && mark<=100) {
System.out.println(" macbook");
}
else
System.out.println("sorry better luck next time");

[start-ecuu]

Good explanation anna . Very easy to understand

[akilanxll-a]

8:31 anna 60 nu potta runtime error varuthu so, >=symbol thaana poddanum?🤔

[thanusanththanus]

unnge video vaa paathu java ennakku full help aa irukku anna thanks for the help anna. then you make video anna

[isalsorandom]

bro the notes cannot be accessible can u see through it and make it downloadble

[DIWAKARJ-pvtq]

6:38 it'll not print Video game bro as the if statement doesnt satisfy the given condition

[sridhar]

Anna " nested if " la
Sys.out.print(s: "eat")
What is the use of (s:) in the above ???

[Harikumar_ganesh]

Bro just just made small mistake
In first condition you put greater than 35 and less than 60. So it will take from 36 to 59.
In second condition you put greater than 60 and less than 90. So it will take from 61 to 89.
Where is 35 and 60?
So the correction is we need to put in first condition "mark>34 && mark<61". Then it will take from 35 to 60❤

[muhammedrashid]

public class nested {
public static void main(String args[])
{
boolean kfc=true;
boolean chicken=true;
boolean pespsi=true;
if(kfc)
{
System.out.println("Myran enter into the kfc");
if(chicken)
{
System.out.println("chicken mathi myrane");
if(pespsi)
{
System.out.println("pepsi kudikku myran");
}
}
}
}
}

[Sugirtha-of]

Anna Ethuku neega print (s:"eating chicken")athula s Ethuku potu irukiga

[dhinagaran]

Bro web development la basic ha theringika vendiya state management and methods pathi oru vedio poduga like (session, viewstate)

[pbgtamilgameryt]

import java.util.Scanner;
public class t2q3 {
public static void main(String args[]){
int a;
Scanner scan = new Scanner(System.in);
System.out.println("Enter the Number");
a=scan.nextInt();
if(a%2==0){
System.out.println("the number is even");
}
else{
System.out.println("the number is odd");
}
}

}

[thanusanththanus]

Anna php language aa oru full video vaa podunge annd

[KrishKarthikSriram]

import java.util.Scanner;

public class EvenOdd
{
public static void main(String[]args)
{
Scanner sc = new Scanner(System.in);
int num = sc.nextInt();
if(num%2==0)
{
System.out.println("it is even");
}
else
{
System.out.println("it is odd");
}
}
}

[m.karthikeyan]

Bro c programming video upload Pannunga

[hijabgirl-]

bro please upload ppt link, it'll be more usefull