Algebra - Ch. 24: Complex Numbers (26 of 28) WHAT IS THE SQUARE ROOT OF i ?

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We will find SQRT( i )=?

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[RainyNight]

I wish I discovered your channel when I was in algebra... Now watching your E&M videos in college..

[btuckervideos]

Good video Michel. Just to say, you forgot to include the negative of the answer found, so:
- root(2)/2 - i.root(2)/2 = - [root(2)/2 + i.root(2)/2] is also a solution, in the same way that (1)^2 = (-1)^2 = 1, (2)^2 = (-2)^2 = 4, etc.

[diatomsaus]

I don't think it exists, had to actually think about it a bit.