Range Sum Query - Mutable | Leetcode 307 | Segment Tree Concepts & Qns | Video 8 | codestorywithMIK

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This is the 8th video of our playlist "Segment Tree Concepts & Questions". Find the Details below :

Video Name : Range Sum Query - Mutable | Leetcode 307 | Segment Tree Concepts & Qns | Video 8 | codestorywithMIK
Video # : 8

🔍 Unraveling Segment Tree : A Journey into the Depths of it.

🎥 Welcome to the 8th Video of my Segment Tree Concepts & Questions Playlist! 🚀 In this enlightening video, we will solve a famous Leetcode Problem on Segment Tree - Range Sum Query - Mutable | Leetcode 307 | Segment Tree Concepts & Qns | Video 8 | codestorywithMIK

🔍 What's Inside ?

🔗 We will see how we can use Segment Tree concepts to easily solve this problem. We will use the same Segment Tree Code Snippet we had studied in starting lectures.

👩‍💻 Who Should Watch ?

This playlist is for everyone but best suited for Freshers who are new to Segment Tree.

🚀 Embark on the Segment Tree Adventure Now!

Problem Name : Range Sum Query - Mutable | Leetcode 307 | Segment Tree Concepts & Qns | Video 8 | codestorywithMIK
Company Tags : META

Summary :
Approach-1: Brute Force
Time Complexity:
Constructor: O(n), where n is the length of the nums array.
Update: O(1)
sumRange: O(n)
Space Complexity: O(n)

Explanation:
This approach stores the input nums array directly in a member variable.
The update operation is simple and efficient, modifying the value at the specified index.
The sumRange operation iterates through the range [left, right] and calculates the sum, which can be slow for large ranges.
Potential Improvement: To improve this approach, a cumulative sum array could be used to make the sumRange operation more efficient.

Approach-2: Segment Tree
Time Complexity:
Constructor: O(n)
Update: O(logn)
sumRange: O(logn)
Space Complexity: O(n)

Explanation:
This approach uses a segment tree to store the sum of elements in different segments of the array.
The buildSegmentTree method constructs the segment tree in O(n) time.
The update operation efficiently updates the segment tree in O(logn) time.
The sumRange operation uses the segment tree to quickly calculate the sum of elements in the specified range in O(logn) time.
Advantages:
This approach is much more efficient for both the update and sumRange operations compared to the brute force method.
It is well-suited for scenarios where there are frequent updates and range sum queries.
In summary, while the brute force approach is straightforward and easy to implement, it becomes inefficient for large arrays and frequent queries. The segment tree approach provides a more efficient solution for dynamic range queries and updates, making it a better choice for large datasets and high-frequency operations.

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✨ Timelines✨
00:00 - Introduction
1:33 - Problem Explanation
5:54 - Coding it up

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I am jealous of those who will find your channel in their 1st year of college 🥲
believe nahi hota khud se bana pa raha hu segment tree 😭😭😭
Love you bhaiya.

gui-codes
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Thanks for this playlist, I never thought that even the most basic will be this easy to implement. Kudos to you for this golden playlist..

satyamraj
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bro....this content is not gold..this is purely diamond....i request you to please also come up with good standard and practice problems for segment tree if possible ...thank you so much sir...and please release a segment tree video every second will be so grateful to you sir...

unknown
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Sir really waited for next video of your playlist

Please keep going and upload at least 3 video of segment tree in a week

BTW best contest on yt❤

_A__Mohit
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Can you please explain combination sum 2 problem? I read your github solution but for some reason was unable to grasp the logic. Thanks in advance if you do. In any case, brilliant work running this channel.

madhavdikshit
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Bhaiya please dp concept bhi complete Kara dijiye....

Btw amazing video

chitranshjain
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literally got a question on segment tree in my google online assesment, wish i would have seen this playlist

gauravghosh
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Hii bhai, can you explain 14th July, Leetcode 3rd & 4th Problem

nileshdeshmukh
welcome to shbcf.ru